Electrostatic field of a sphere

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SUMMARY

The electrostatic field of a non-conductive sphere with a radius R and a uniform charge density ρ0 can be analyzed using Gauss's law. The discussion highlights the need to consider two distinct regions: inside the sphere (r' < R) and outside the sphere (r' ≥ R). The electric field is a vector quantity, and the solution must account for both regions to provide a complete understanding of the electrostatic field behavior.

PREREQUISITES
  • Understanding of Gauss's law in electrostatics
  • Familiarity with vector fields and their properties
  • Knowledge of charge density distributions
  • Basic calculus for solving integrals
NEXT STEPS
  • Study the application of Gauss's law for different charge distributions
  • Learn about electric field calculations for spherical symmetry
  • Explore the concept of vector fields in electrostatics
  • Investigate the mathematical techniques for solving integrals in electrostatics
USEFUL FOR

Physics students, electrical engineers, and anyone studying electrostatics or working with electric fields in spherical geometries.

gebhaard
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Homework Statement
What is the electrostatic field of a non-conductive sphere (it's radius is R) which has a density charge distribution inside? ρ0 and R are parameters.
Relevant Equations
Gauss' law
What is the electrostatic field of a non-conductive sphere (it's radius is R) which has a
1585772034040.png

density charge distribution inside? ρ0 and R are parameters.

I started solving this with Gauss's law:
1585771866519.png

then:
1585771887327.png

Solving the integral:
1585771903343.png

This means the electrostatic field of the sphere in r is:
1585771919260.png


Can you check if is this correct? If it isn't, what is the problem?
Thanks.
 
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Can you not simplify that answer? Also, the electric field is a vector.
 
Also, there are two regions in space with different functional dependence for the field, ##r'<R## and ##r' \geq R##. You found the field in the former but not the latter.
 

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