Electrostatic force between 2 hemispheres

In summary, the force of repulsion between the northern and southern hemispheres of a metal sphere with radius R and total charge Q can be calculated by integrating over the area of the sphere using the equation Fz = ∫fz dA = ∫σEav cosθ R^2sinθ dθ dφ = ∫(Q/2*4πR^2)(Q/4πεoR^2)cosθ R^2sinθ dθ dφ. This calculation takes into account the fact that the electric field is zero inside the conductor and only present outside, causing the force to separate the hemispheres. It is important to note that this calculation is for one hemisphere only and the
  • #1
mathnerd15
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Homework Statement


A metal sphere of radius R carries a total charge Q, what is the force of repulsion between the northern and southern hemispheres

Homework Equations


[tex]\large f=\sigma Eav=1/2 \sigma(Eabove+Ebelow). \\Fz=\int fz dA =\int \sigma Eav cos\theta R^{2}sin\theta d\theta d\phi=\int \frac{Q}{2*4\pi R^2}\frac{Q}{4\pi\epsilon o R^2}cos\theta R^{2}sin \theta d\theta d\phi[/tex]

The Attempt at a Solution


I'm not sure why you don't integrate the R^2 in spherical coordinates? when you integrate are you summing force differential elements from each piece from the volume of the sphere? also since E is 0 inside the conductor and there is a force only outside, the force tends to separate the hemispheres and then doesn't the force cancel (this seems to be the calculation for one hemisphere only)? maybe I don't understand the integral sum of the force elements?
 
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  • #2
You're not integrating over the volume; you're integrating over the area. A sphere is a two-dimensional surface.
 
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  • #3
thanks, sorry so I am summing the differential force elements in the z direction from the surface of the sphere by taking Ez? but aren't there radial force elements in all directions which cancel in the +z -z with azimuthal symmetry? or if you calculate the force of each hemisphere then wouldn't the integration be from 0 to pi for phi instead of 2 pi?

do most people take mechanics before EM like from some text?
 
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1. What is the electrostatic force between two hemispheres?

The electrostatic force between two hemispheres is the force of attraction or repulsion between two charged objects. It is a fundamental force in nature that arises due to the presence of electric charges.

2. How is the electrostatic force between two hemispheres calculated?

The electrostatic force between two hemispheres can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. The formula is F = k * (q1 * q2) / r^2, where F is the force, k is the Coulomb's constant, q1 and q2 are the charges of the two hemispheres, and r is the distance between them.

3. What factors affect the electrostatic force between two hemispheres?

The electrostatic force between two hemispheres is affected by the magnitude of the charges on the objects, the distance between them, and the medium between them. It is also affected by the presence of other charges in the surrounding environment.

4. Can the electrostatic force between two hemispheres be attractive and repulsive at the same time?

No, the electrostatic force between two hemispheres can only be either attractive or repulsive, depending on the signs of the charges. Like charges (both positive or both negative) repel each other, while opposite charges (one positive and one negative) attract each other.

5. How does the electrostatic force between two hemispheres compare to other fundamental forces?

The electrostatic force between two hemispheres is one of the four fundamental forces in nature, along with gravity, weak nuclear force, and strong nuclear force. It is the strongest force among these four, but it has a limited range and only affects electrically charged objects.

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