Electrostatic Force: Effects of Distance

Click For Summary
SUMMARY

Electrostatic force between two charged objects decreases by a factor of \(\frac{1}{4}\) when the distance between them is doubled, following Coulomb's Law. This is analogous to gravitational force, which also decreases by \(\frac{1}{4}\) under the same conditions, as both forces are governed by inverse square laws. The equations governing these forces are \(F_e = k_e\frac{|q_1q_2|}{d^2}\) for electrostatic force and \(F_g = G\frac{m_1m_2}{d^2}\) for gravitational force, where \(k_e\) and \(G\) are constants specific to electrostatics and gravity, respectively.

PREREQUISITES
  • Understanding of Coulomb's Law and its equation
  • Familiarity with Newton's Law of Universal Gravitation
  • Basic knowledge of inverse square laws
  • Concept of electric charge and gravitational mass
NEXT STEPS
  • Study the implications of Coulomb's Law in electrostatics
  • Explore applications of inverse square laws in physics
  • Investigate the role of Coulomb's constant in electrostatic calculations
  • Learn about the relationship between electric fields and forces
USEFUL FOR

Physics students, educators, and professionals interested in electrostatics, gravitational interactions, and the mathematical principles governing force relationships.

Dustinsfl
Messages
2,217
Reaction score
5
How does electrostatic force vary between two objects if the distance is doubled?

I know with gravitational force as the distance doubles the force decreases by \(\frac{1}{4}\).
 
Mathematics news on Phys.org
dwsmith said:
How does electrostatic force vary between two objects if the distance is doubled?

I know with gravitational force as the distance doubles the force decreases by \(\frac{1}{4}\).

Gravitational and Electrostatic force fields are both inverse square fields. In particular for gravity (known as Newton's Law of Universal Gravitation),

\[F_g = G\frac{m_1m_2}{d^2}\]

where $G$ is the gravitational constant, $m_1$ and $m_2$ are the masses of objects and $d$ is the distance between these two objects.

Likewise for electrostatic force (known as Coulomb's Law),

\[F_e = k_e\frac{|q_1q_2|}{d^2}\]

where $k_e$ is Coulomb's constant, $q_1$ and $q_2$ are the signed charges of the particles, and $d$ is the distance between these two particles.

So if the distance between any two particles/objects is doubled in either case, the force decreases by a factor of $\dfrac{1}{4}$.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
14
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 14 ·
Replies
14
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
755
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 11 ·
Replies
11
Views
5K