Electrostatic Forces on Particles

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Homework Help Overview

The discussion revolves around the electrostatic forces acting on an Astatine 219 nucleus and an alpha particle during alpha decay, specifically focusing on calculating the ratio of their velocities given their initial conditions.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between kinetic energy and velocity ratios, with one suggesting the use of conservation of kinetic energy as a method to approach the problem.

Discussion Status

Some participants express confidence in using kinetic energy conservation, while others question whether this approach is valid given the differences in mass between the two particles. There is an ongoing exploration of how to relate the kinetic energies and velocities without reaching a definitive conclusion.

Contextual Notes

Participants note the challenge of applying force concepts due to the variable nature of force with distance, indicating a focus on energy considerations instead.

DMac
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[SOLVED] Electrostatic Forces on Particles

"An Astatine 219 nucleus and an alpha particle at a spacing of 1.5 x 10^-15 m are formed during alpha decay. If the initial velocity of the two particles is zero, calculate the ratio of their velocities."

I was thinking of making a ratio of their kinetic energy, but I'm not sure if that's simplifying the problem too much.

If I make a ratio, I get:
.5 x m1 x v1^2 : .5 x m2 x v2^2
...

v1
--- = sqrt [m2 / m1]
v2

Is this right?
 
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Seems right to me. Conservation of kinetic energy is a handy trick!
 
I'm just not sure if it can be done any other way...because I certainly cannot use force (since force varies with the distance, just like the gravitational potential well). So all I could think of was energy.

However, I'm particularly unsure because my manipulation basically equates the two kinetic energies; that is, the energy of the alpha particle is the same as that of the astatine particle.
 
Yes, the energies are the same, but the velocities are different.
This is due to the different masses.
 

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