Electrostatic Potential of a Charged Metallic Shell

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SUMMARY

The discussion centers on calculating the charge of a charged metallic spherical shell with a radius of 2.75 cm and a potential of 2.5 kV at a distance of 6.0 cm from its center. The formula used is V = kQ/r, where V is the potential, k is Coulomb's constant (8.99 x 10^9 N m²/C²), and Q is the charge. The calculated charge on the shell is 1.7 x 10^-8 Coulombs, confirming that the approach and units used are correct, with the radius being relevant for further calculations.

PREREQUISITES
  • Understanding of electrostatics and electric potential
  • Familiarity with Coulomb's law and the constant k
  • Basic algebra for solving equations
  • Knowledge of unit conversions, particularly between centimeters and meters
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  • Learn about the behavior of electric fields around spherical conductors
  • Investigate the implications of Gauss's law in electrostatics
  • Study the effects of varying charge distributions on potential and field strength
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Homework Statement



Given a charged metallic spherical shell of radius a=2.75cm, with a potential of 2.5kV a distance of r=6.0cm from the center of the shell, what is the charge on the shell? Calculate the potential on the surface of the shell.

Homework Equations



V=kQ/r

The Attempt at a Solution



I am assuming that I should just insert values into the equation, so...

2500V = (8.99E9)(Q)/(.060m)
Q = 1.7E-8

Is this calculation correct? I am not sure if the radius of the shell needs to be considered. Also, am I using the right units and are the units of Q Coulombs?
 
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Calculation is correct! Radius will be considered in the second part of the question.:smile:
 

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