Electrostatic potential of a cube with charge density

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SUMMARY

The discussion centers on calculating the ratio of electrostatic potential at the center of a uniformly charged cube with charge density ρ to that at one of its corners. Participants suggest using Gauss's law and symmetry arguments to derive the electric field within the cube. The key equations referenced include Φ = E·A and ΔV = Work done/charge = -E·D. The problem remains unsolved, indicating a need for further exploration of these concepts.

PREREQUISITES
  • Understanding of electrostatic potential and electric fields
  • Familiarity with Gauss's law
  • Knowledge of charge density concepts
  • Basic grasp of vector calculus in electrostatics
NEXT STEPS
  • Study the application of Gauss's law in three-dimensional charge distributions
  • Learn about the calculation of electric fields for geometrically symmetric charge distributions
  • Explore the concept of electrostatic potential in relation to charge density
  • Investigate the use of superposition principle in electrostatics
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Students and educators in physics, particularly those focusing on electrostatics, as well as researchers interested in charge distribution effects in three-dimensional geometries.

Yashasvi Grover
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Homework Statement



Consider a uniformly charged cube with uniform charge density ρ.The ratio of electrostatic potential at the centre of the cube to that of one of the corners of the cube is?
A hint on how to approach the problem's solution would be appreciated.(whether to use gauss law or not etc.)

Homework Equations


Phi=E.A and
ΔV=Workdone/charge=-E.D

The Attempt at a Solution


I tried to use Gauss law and symmetry argument to find electric field inside the cube,but failed.Help would be appreciated.
 
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Yashasvi Grover said:

Homework Statement



Consider a uniformly charged cube with uniform charge density ρ.The ratio of electrostatic potential at the centre of the cube to that of one of the corners of the cube is?
A hint on how to approach the problem's solution would be appreciated.(whether to use gauss law or not etc.)
2. Homework Equations

Phi=E.A and
ΔV=Workdone/charge=-E.D

The Attempt at a Solution


I tried to use Gauss law and symmetry argument to find electric field inside the cube,but failed.Help would be appreciated.
Consider it made of eight half-sized cubes.
 

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