Electrostatic problem (point charges)

Click For Summary
SUMMARY

The discussion revolves around solving an electrostatic problem involving point charges and the derivation of electric field equations based on Coulomb's Law. The user expresses confusion regarding the derivation of a specific result, particularly the fourth root of 2, in relation to the electric field component Ey. The conversation highlights the importance of correctly applying the electric field equations and ensuring accuracy in calculations, as indicated by the suggestion to double-check the solution for missing negative signs.

PREREQUISITES
  • Coulomb's Law for electric fields
  • Understanding of electric field components (Ey and Ex)
  • Basic algebra for solving equations
  • Knowledge of point charge configurations
NEXT STEPS
  • Review the derivation of electric field equations from Coulomb's Law
  • Study the concept of superposition in electric fields
  • Learn about the significance of charge polarity in electrostatics
  • Explore graphical methods for visualizing electric field lines
USEFUL FOR

Students studying electrostatics, physics educators, and anyone seeking to deepen their understanding of electric fields and point charge interactions.

martinskibg
Messages
2
Reaction score
0

Homework Statement



http://www.freeimagehosting.net/uploads/3e00ce8695.gif


Homework Equations



Electric field equation derived from Coloumb's Law (given on the screenshot above).

The Attempt at a Solution



Solution is given in the form of answer sheet:

http://www.freeimagehosting.net/uploads/0d23171fd2.gif

My problem is - I can't understand how the result in point b) is derived. My best guess was deriving an equation for Ey and equate it to 0 (taking into account the new values for a, b and Q). From there a relation between b2 and b can be derived. But I really don't understand why the result is fourth root of 2. My guess was square rooth of 2? It's unclear to me but it seems that if Ey has to be negated, than Q2 has an opposite charge compared to the other ones? Where is this "point of origin"? I'm really confused :(.
 
Physics news on Phys.org
martinskibg said:
My best guess was deriving an equation for Ey and equate it to 0 (taking into account the new values for a, b and Q). From there a relation between b2 and b can be derived.

That seems like a good plan to me. Just remember, that at the origin [itex]x=y=0[/itex].

Also, you might want to double check the solution to part (a) that you posted, because I see two missing negative signs after just a quick glance at it, and there may be more errors.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
1
Views
905
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K