Electrostatics charged spheres problem

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Homework Help Overview

The discussion revolves around electrostatics, specifically focusing on the behavior of charged spheres and the forces involved with a charged ring and a point charge. Participants explore the implications of charge leakage and the complexities of calculating electric fields and forces in these scenarios.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the mechanisms behind charge leakage from the spheres, questioning the principles that lead to this phenomenon. They also explore the challenges of calculating the electric field and forces related to a charged ring and a point charge, with attempts to integrate and derive expressions for force.

Discussion Status

Some participants have provided insights into the causes of charge leakage, while others are seeking clarification on the necessity of this leakage in the context of the problem. There is ongoing exploration of the mathematical approaches to the second problem, with some participants offering partial calculations and questioning the methods used.

Contextual Notes

Participants mention the influence of environmental factors, such as atmospheric ions and moisture, on charge leakage. There is also a reference to the perceived complexity of the problems, with one participant labeling the first problem as artificial in nature.

Kolahal Bhattacharya
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1)Two small equally charged spheres, each of mass m, are suspended from the same point by silk threads of length l.The distance between the spheres x<<l.Find the rate dq/dt with which the charge leaks off each sphere if their approach velocity varies as v=a/(x)^0.5, a is a constant.
The problem can be done by expressing q^2 in equilibrium condition and then differentiating w.r.t. time.But I wonder why the charge leakage will occur?What principle makes it and how?
2)A thin wire ring of radius R has an electric charge q. What will be the increment of the force streatching the wire if a point charge qo is placed at the ring's centre?
It appeared to me that the direct mathematical formulation of E field, inside and outside the ring is rather difficult.so i tried to calculate the potential due to the ring and point charge.But, the integration to find contribution of the ring turned hopelessly difficult.Please help.
Kolahal Bhattacharya.
 
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1) Due to ions in atmosphere cancelling charges on the spheres. These charged particles can originate from various sources - natural radioactivity in the vicinity/ground/materials in the surroundings.

A larger source of discharge works as follows. Any uncharged particle approaching the sphere will be induced with an opposite charge closest to the sphere. This will attract it to the sphere. Once stuck on it it will gain the same charge as the sphere (the particle was initially neutral). Now it will be repelled by the sphere, flying off into space carrying away some of the charge on the sphere.

Another possible route of discharge happens when the threads absorb moisture out of the atmosphere. This will make them conductive, providing a path for discharge.
 
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I understand.But could you please clarify, what feature of this problem makes the charged sphere to gradually leak out the charge.In other words, why the charge leakage is necessary in this problem?
What about my next problem?
 
Kolahal Bhattacharya said:
I understand.But could you please clarify, what feature of this problem makes the charged sphere to gradually leak out the charge.In other words, why the charge leakage is necessary in this problem?

To be honest with you, this is one of Irodov's artificial sounding problems :smile:

What about my next problem?

On-axis field due to a ring is fairly easy to compute. But you don't need it here.

When you place the point charge at the center of the ring, the ring experiences a net outward (repulsive) force. Can you calculate the force on an element of the ring due to the charge and integrate it?
 
I did it:
dF=k ∫(q0λdl)/r^2
put dl=r dφ
have dF=k ∫(q0λr dφ)/r^2
Then, dF=(kq0λ/r) ∫dφ
integrating o to 2 pi, F=...
The answer is (Irodov):∆T=(qqo)/(8π^2ε0r^2)
So this is not the way you led.
 
Yeah that's it.
 

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