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Homework Statement
Homework Equations
The Attempt at a Solution
Option (a), because the potential is 0 on the surface, and potential due to point charge is positive so there must be negative charge on the surface. Since opposite charges attract each other, there is an attractive force between the sphere and the point charge.
(b) As the potential due to point charge is different at different points of surface, the surface charge density should not be same everywhere. So, this is correct.
(c) In case of electrostatics, electric field inside a conductor is 0. So, this is correct.
(d) By memory, I feel that this option is correct. Is there anyway to find out this information without solving the question fully?
(e) For large d, the point charge and the sphere will act as a dipole and so the potential falls off as ## \frac { 1} {d^2} ## .
So, the required option is (e).
Is this correct?
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