Elementary Measure Theory Question

Click For Summary
SUMMARY

The discussion centers on a claim in introductory measure theory regarding the set B = ℚ ∩ [0,1] and its finite open cover {I_k}_{k=1}^n. The claim asserts that the sum of the outer measures of the open cover must be at least 1, expressed as ∑_{k=1}^n m^*(I_k) ≥ 1. The proof provided highlights that at least one interval I_j must contain infinitely many elements of B, leading to the conclusion that m^*(I_j) must equal 1. However, the proof's reliance on the 'WLOG WMA' statement is criticized for lacking rigor, indicating a need for more detailed justification.

PREREQUISITES
  • Understanding of measure theory concepts, specifically outer measure.
  • Familiarity with the properties of rational numbers within real intervals.
  • Knowledge of open covers and their significance in measure theory.
  • Ability to construct and critique mathematical proofs.
NEXT STEPS
  • Study the concept of outer measure in detail, focusing on its properties and applications.
  • Explore the construction of open covers and their role in measure theory.
  • Review rigorous proof techniques in measure theory to enhance proof-writing skills.
  • Investigate the implications of the Baire category theorem in relation to measure theory.
USEFUL FOR

Students and educators in mathematics, particularly those studying measure theory, as well as mathematicians seeking to refine their proof-writing skills and understanding of measure-related concepts.

ntsivanidis
Messages
4
Reaction score
0
Hey guys, below is a small question from introductory measure theory. Maybe be completely wrong on this, so if you could point me in the right direction I'd really appreciate it.

Claim: Let [tex]B=\mathbb{Q} \cap [0,1][/tex] and [tex]\{I_k\}_{k=1}^n[/tex] be a finite open cover for [tex]B[/tex]. Then [tex]\sum_{k=1}^n m^*(I_k) \geq 1[/tex]

Proof: Let [tex]\ B = \{q_k\}_{k=1}^\infty[/tex].Since [tex]{I_k\}_{k=1}^n[/tex] is a finite cover, there must be at least one [tex]j \in \{1,\dots,n\}[/tex] s.t. [tex]I_j[/tex] contains infinitely many elements of [tex]B[/tex].Fix [tex]\varepsilon > 0[/tex]. WLOG, WMA [tex]I_k=(q_k - \frac{\varepsilon}{2(n-1)}, q_k + \frac{\varepsilon}{2(n-1)}) \ni q_k \ \forall \ k \neq j[/tex]. Then [tex]\sum_{k=1}^n m^*(I_k) = \sum_{k\neq j} m^*(I_k) + m^*(I_j)=\varepsilon + m^*(I_j) \geq m^*(I_j)=1[/tex] since [tex]m^*([0,1]\backslash \mathbb{Q})=1 \ \Box[/tex]
 

Attachments

  • Screen shot 2010-10-09 at 8.03.52 PM.png
    Screen shot 2010-10-09 at 8.03.52 PM.png
    11.5 KB · Views: 518
  • proof_tex.txt
    proof_tex.txt
    1,022 bytes · Views: 272
Last edited:
Physics news on Phys.org
Although the statement is correct, the 'WLOG WMA' part of the proof is too sweepy. You must provide details if the proof is to sound rigorous.
 
Thanks! Along what lines should I proceed? It's very shaky from that point onwards and I'm stumped for something more concrete. If you could describe a sketch, that would be great. Cheers
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K