Elevation of Sun above water surface

[Agarb]

Homework Statement

An underwater scuba diver sees the Sun at an apparent angle of 44.5° above the horizontal. What is the actual elevation angle of the Sun above the horizontal? (Use 1.333 for the index of refraction of water.)

Homework Equations

n₁sin(Θ₁) = n₂sin(Θ₂)

The Attempt at a Solution

I've been doing:

1.333*sin(43) = .9091

sin^-1(.9091)= 65.38

90-65.38 = 24.62 degrees

Where am I going wrong?? The answer is 12.9 degrees, but every time I try to do it, I get 24.62 degrees.

 

[mfb]

Where does the 43 come from?

I get 18 degrees.

 

[Agarb]

Where does the 43 come from?

I get 18 degrees.

What are the steps you're taking?

 

[haruspex]

what are the steps you're taking?

90-44.5 = ?

 

[mfb]

What are the steps you're taking?

The same steps as you, just with the right numbers. See the open question in post 2 and 4.

 

[Agarb]

I don't understand where you see a 43?

 

[mfb]

The Attempt at a Solution

I've been doing:

1.333*sin(43[/size]) = .9091

sin^-1(.9091)= 65.38

90-65.38 = 24.62 degrees

Where am I going wrong?? The answer is 12.9 degrees, but every time I try to do it, I get 24.62 degrees.

I highlighted it.

 

[Agarb]

Shoot sorry, I copied it over and forgot to change it. It should be 44.5

But I still don't get the correct answer

 

[haruspex]

Shoot sorry, I copied it over and forgot to change it. It should be 44.5

No, not that either: 44.5° above the horizontal

 

[Agarb]

No, not that either: 44.5° above the horizontal

What does that mean?? I tried 90-44.5 and 180-44.5 but it doesn't work. Am I going crazy??

 

[haruspex]

I tried 90-44.5

That should do it. Please post you working.