Elevator Tension Calculation: Finding Force with Fnet and Newton's Laws

[t00kool]

Homework Statement

An elevator with a mass of 650 Kg supported by steel cable. What is the tension in the calbe when the elevator is accelerated upward at the rate of 3.00 m/s^2

Homework Equations

well he gives the equations that we can use as: Fnet=ma, w=mg and g=9.8m/s^2
I don't know what W means. Also he never taught us how to find tension.

The Attempt at a Solution

Well I used Fnet: 650KG * 3.00m/s^2= ANS.

If this is right can someone explain to me how.


x

Please Help.

 

[rock.freak667]

The Attempt at a Solution

Well I used Fnet: 650KG * 3.00m/s^2= ANS.

If this is right can someone explain to me how.

well the resultant acceleration is 3 ms$^{-2}$
so the net force,$F_{net}=650*3=1950N$

The weight of the elevator is W.
The tension in the cables holding the elevator is T.

If the weight is acting down and tension is acting up, and the resultant of these 2 is in an upward direction. What would be an equation relating the the resultant (net) force, the tension and weight?