An elevator with a mass of 650 Kg supported by steel cable. What is the tension in the calbe when the elevator is accelerated upward at the rate of 3.00 m/s^2
well he gives the equations that we can use as: Fnet=ma, w=mg and g=9.8m/s^2
I don't know what W means. Also he never taught us how to find tension.
The Attempt at a Solution
Well I used Fnet: 650KG * 3.00m/s^2= ANS.
If this is right can someone explain to me how.