Elliptical Orbit Homework: Calculate r1/r0

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Homework Help Overview

The discussion revolves around calculating the ratio of the nearest and furthest distances (r1/r0) of Earth from the Sun in an elliptical orbit, using a provided polar coordinate equation. The subject area includes concepts of orbital mechanics and properties of ellipses.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the maximum and minimum values of cosine to determine distances in the orbit equation. There are attempts to clarify the correct form of the equation and the meaning of the constant p. Some participants question the validity of the initial approach and suggest using critical thinking or calculus to find extrema.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and equation. Some guidance has been offered regarding the use of critical angles and the relationship between the equation's denominator and the radial distance. There is no explicit consensus on the correct approach yet.

Contextual Notes

Participants express uncertainty about the equation provided in the homework statement and the meaning of the constant p. There is also a mention of the need for further clarification on the eccentricity value used in the context of the problem.

Cryphonus
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Homework Statement



The equation of the elliptical orbit of Earth around the sun in
polar coordinates is given by
r =ep/1 − e cosa
where p is some positive constant and e = 1/60. Let r0 and r1
denote the nearest and the furthest distance of the Earth from
the sun. Calculate r1/r0

Homework Equations



the one that is provided with the question

The Attempt at a Solution



I simply tried to give the max and min values for Cosa, which is 90 and 0 degrees.But I am not really sure if its right,Glad if you can help me here...

Thanks a lot

Cryphonus
 
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Cryphonus said:
I simply tried to give the max and min values for Cosa, which is 90 and 0 degrees.But I am not really sure if its right,Glad if you can help me here...
That's not right. Try drawing a picture with the Sun at one of the foci of the ellipse. For what angles does the distance between the Earth and Sun reach minimum and maximum?
 
0 - 180 degrees?
 
Don't guess!

Do you know calculus? If you do you should easily be able to determine these critical angles. Even without calculus, a bit of critical thinking is all that is needed. The value of [itex]\cos a[/itex] ranges between -1 and +1. Given that, what are the minimum and maximum values for the denominator in your equation, [itex]r=ep/(1-e\cos a)[/itex]? Finally, are the extrema in the denominator related to the extrema of the radial distance?

BTW, that equation does not look quite right. The orbit equation in standard form is [itex]r=p/(1+e\cos\theta)[/itex].
 
I didnt guessed it :) .It just i took the max and min values as 0 and 1 which is ofcourse not true, so silly of me (: . I don't know about the equation it is given in the question.. but if you have any idea about what the question says "where p is some constant" i would be happy to hear.I never heard such a constant called "p" about this subject...
 
One way to express the radial distance as a function of angle for an elliptical orbit is

[tex]r=\frac {a(1-e^2)}{1+e\cos \theta}[/tex]

where a is the semi-major axis, e is the eccentricity of the orbit, and θ is the "true anomaly", the angle between the line from the focus to the closest approach ("perifocus") and the line from the focus to the current position.

An alternative parameter to the semi-major axis a for characterizing the size of an ellipse is the semi-latus rectum, [itex]p=a(1-e^2)[/itex]. The semi-latus rectum is also given by

[tex]p=\frac{h^2}{GM}[/tex]

where h is the specific orbital angular momentum, G is the universal gravitational constant, and M is the mass of the central object (e.g., the Sun).

Note that there is no factor of e in either form of the orbit equation.
 
Ok thanks a lot i will ask around in the collegea about e
 

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