I know that if a beam is balanced on a central pivot point with equal weights on either end, the beam will be in equilibrium. If the pivot point were to to be moved to, say, a quarter of the distance from one end, then obviously more weight would be required on the "short" side of the beam to maintain equilibrium. What I am after is the simple formula for determining where on the beam should the pivot point be for any two given differing weights. I did say it was embarrassingly elementary ... :-( While I am at it, can I throw in a pendulum question as well ... Given two pendulums of identical construction (ie length and size of pendulum) , but the weight of the pendulum bob on pendulum A is ten times heavier than the weight of the pendulum bob on pendulum B, will pendulum B reach inertia before pendulum A (assuming that the initial start point is identical for both) or will both come to rest at the same time ? FWIW both pendulums are pivoting on identical ball races and the pendulum arm is rigid.