Emergency Braking: Stopping Distance of 48m

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SUMMARY

The discussion focuses on calculating the stopping distance of an automobile traveling at 16 m/s with a negative acceleration of 4.0 m/s². The driver's reaction time is 1.0 second, during which the car travels 16 meters. The braking distance is calculated using the equation V² - V₀² = 2*a*x, resulting in an additional 32 meters of stopping distance. The total stopping distance is therefore 48 meters, confirming the initial query.

PREREQUISITES
  • Understanding of kinematic equations, specifically V² - V₀² = 2*a*x
  • Knowledge of basic physics concepts such as acceleration and reaction time
  • Familiarity with units of measurement in physics (meters, seconds)
  • Ability to perform basic algebraic calculations
NEXT STEPS
  • Study the effects of different acceleration rates on stopping distances
  • Learn about the impact of driver reaction time on overall stopping distance
  • Explore real-world applications of kinematic equations in automotive safety
  • Investigate how road conditions affect braking performance
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding vehicle dynamics and safety measures related to braking distances.

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Homework Statement


An automobile is traveling at 16 m/s. The driver perceives a need to stop and applies the
brakes producing a (negative) acceleration of 4.0 m/S2. Take the reaction time of the
driver, the time to move from the go pedal to the stop pedal, as 1,0 s.

Homework Equations


How far does it take for the car to stop?

The Attempt at a Solution


during his reaction time, he traveled d=16*1=16m.
we calculate the distance of braking:
V2-V02=2*a*x
x= 32m.
the whole distance is 16+32=48m and that's what we have been asked to find.
 
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same kind of question. and you have answered it yourself.
 

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