EMF across a loop with one end in a parallel plate capacitor

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Homework Help Overview

The discussion revolves around the behavior of electromagnetic fields and currents in a loop with one end connected to a parallel plate capacitor. Participants explore the implications of steady current assumptions and the uniformity of conductivity in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants question the assumptions regarding steady current and uniform conductivity, discussing the conditions necessary for electrical current and the implications of a capacitor's charging state. There is also a consideration of whether a current would persist if a conductor is placed between the capacitor plates.

Discussion Status

The discussion is ongoing, with various interpretations being explored regarding the presence of current in the loop and the effects of the capacitor. Some participants have offered guidance on the uniformity of conductivity, while others express uncertainty about the existence of current under the given conditions.

Contextual Notes

There is a lack of clarity regarding the assumptions made about the current and the setup of the capacitor, which may influence the conclusions drawn in the discussion.

Pushoam
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Homework Statement


upload_2017-9-1_14-58-1.png

Homework Equations

The Attempt at a Solution


Assuming the current is steady,
I = JA, where J is the current density and A is the cross- sectional area
##E = J/\sigma##
Can I take ##\sigma ## uniform here ?
 
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What is needed for an electrical current?
All conditions fulfilled?
How about your assumption?

The sigma can be taken uniform here.
 
Pushoam said:
Assuming the current is steady
Which current? Are you assuming that the capacitor is charging?
 
cnh1995 said:
Which current? Are you assuming that the capacitor is charging?
Current in the loop.
Is the other end touching the capacitor?
 
efdee said:
The sigma can be taken uniform here.
Then, the potential difference across the resistance will be V = Eh
So, current I = Eh/R , but this creates perpetual motion machine which is wrong.
 
Suppose you took any piece of conducting material and suddenly placed it between the plates of a charged capacitor. Would you get any current in the material? If so, would the current last very long? Why or why not?
 
It is not very clear. However I believe
there is no current at all !
 
efdee said:
It is not very clear. However I believe
there is no current at all !

that is incorrect

why would you say that ?
 

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