EMI Quickies: Get Answers to Your Questions

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Homework Help Overview

The discussion revolves around electromagnetic induction (EMI) and the behavior of current in circuits, particularly in relation to inductance, resistance, and the effects of closing and opening switches. Participants explore various aspects of these concepts through specific questions and scenarios.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of induced EMF and current in circuits, questioning how these change over time when switches are closed or opened. There are inquiries about the relationship between current, resistance, and battery characteristics. Some participants also raise points about the implications of electron movement and heating in the context of magnetic fields.

Discussion Status

The discussion is active with multiple participants contributing their thoughts and equations related to the behavior of current in circuits. Some guidance has been offered regarding the mathematical relationships involved, but there is no clear consensus on certain points, particularly concerning the implications of resistance and electron behavior.

Contextual Notes

Participants are navigating complex concepts within the constraints of homework rules, which may limit the depth of exploration. There are ongoing questions about assumptions related to circuit behavior, particularly when switches are open or closed.

cupid.callin
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#1
No idea.

#2
Please someone explain me the question. From what I have understood, I think it’s because on connecting wires, it will form a closed loop and will induce an opposing EMF which will induce current in circuit and which will provide an opposing torque to the motion.

#3
Yes, start at instance battery is connected and continue to rise till infinity as current in first will also me maximum at infinity and will keep on increasing till then

#4
Same reason as third, current will be 0 at infinity

#5
Doesn’t inductance only depend on just geometry of solenoid? Then why will it change for ends?

#6
I guess at center as magnetic field lines are denser at center.

#7
The rod will magnetize so field and flux will increase, but answer is (a), (b), (c)

#8
Answer says that (d) is wrong, why? While electron will shift at B, they will collide and produce heat, right?
 

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1. How does the current change with time after the switch is closed? What is the time derivative of the current at t=0? And how much is the change of the current when the switch is opened? How long can it last to open a switch?

ehild
 
For closing: i = io (1 - e-t/τ)
so di/dt = ioe-t/τ / τ
at t=0, i = io

For opening, i = io e-t/τ
di/dt = -io e-t/τ / τ
di/dt = -io / et/τ τ

As 1 > e-x > 0 for x>0

di/dt in opening is greater than one ... right?
 
What is Io when the switch is closed? How is it related to the battery and the resistance in the circuit? There is always some resistance: the inner resistance of the battery, the resistance of the wires, the resistance of the coil (it is made of wire which has some resistance)

Can current flow at all when the switch is open? The equation you wrote refers to the case when the battery is short-circuited at t=0, at the current is io at that instant. It is not breaking the circuit.

ehild
 
8. no reason it will not heat up, unless it has no resistance or there is only 1 correct answer, in which case end A will become positively charged answer (C) (because of Lorenz force).
 
cupid.callin said:
#8
Answer says that (d) is wrong, why? While electron will shift at B, they will collide and produce heat, right?
There is no more movement of electrons than there is for a stationary rod.
 

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