Why is a black surface a better emitter of IR than a silvered surface?

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    Absorption Emission Ir
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SUMMARY

A black surface is a superior emitter of infrared (IR) radiation compared to a silvered surface due to its ability to absorb and emit thermal radiation more effectively. This phenomenon is explained by the principles of blackbody radiation, where a matte black surface approaches the ideal characteristics of a blackbody, maximizing emission at all temperatures. In contrast, a silvered surface reflects IR radiation, resulting in lower emissivity when warm. This discussion highlights the fundamental differences in thermal properties between these two types of surfaces.

PREREQUISITES
  • Understanding of blackbody radiation principles
  • Knowledge of emissivity and reflectivity concepts
  • Familiarity with thermal radiation and heat transfer
  • Basic physics of infrared radiation
NEXT STEPS
  • Research the Stefan-Boltzmann Law and its application to thermal radiation
  • Explore the concept of emissivity in materials science
  • Learn about the applications of blackbody radiation in thermal imaging
  • Investigate the differences between matte and reflective surfaces in thermal applications
USEFUL FOR

Physicists, engineers, and anyone interested in thermal dynamics, material science, or infrared technology will benefit from this discussion.

Glenn G
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I can just get the idea of a silvered surface reflecting IR and a black surface absorbing IR (analogous to how light behaves) but I can't see how a silvered surface, if warm is a poorer emitter than a Matt black surface, if warm?
Would appreciate any help without going too in depth.
Regards,
G.
 
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Glenn G said:
I can just get the idea of a silvered surface reflecting IR and a black surface absorbing IR (analogous to how light behaves) but I can't see how a silvered surface, if warm is a poorer emitter than a Matt black surface, if warm?
Would appreciate any help without going too in depth.
Regards,
G.
hi there :smile:

there's no point me typing out a long answer when some one else has already done so ...

https://physics.stackexchange.com/questions/159856/why-is-black-the-best-emittercheers
Dave
 

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