I Emission probability in blackbody spectrum derivation

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The discussion centers on the concept of emission probability in the context of blackbody spectrum derivation. There is a clarification that the emission probability, denoted as p, is not a probability density but rather a straightforward probability indicating whether emission has occurred. The presenter does not explicitly state this distinction, leading to some confusion. Understanding this difference is crucial for accurately interpreting the blackbody spectrum. Overall, the emphasis is on correctly defining the nature of the emission probability in this context.
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No, ##p## is not probability density. It's just the probability that emission happened.
 
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Thread 'Angular Momentum Vector and Its Magnitude'

For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...
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