# Empty relation and equivalence classes

385sk117
These two terms would be the simplest terms in the set theory as they are on the first chapter in my textbook. But why can't i understand it?
In my textbook it says

A relation R in a set is a set of ordered pairs, so any subset of a set of ordered pairs will be a relation. This includes the empty set which is referred to as the empty relation.

What is this mean? empty set = empty relation? and if so then why empty relation is symmetric as well as transitive? My teacher said it is done by default but i still can not understand it.

In case of equivalence class i understand the concept and i thought it was easy. An equivalnce relation on Set partitions Set into subsets which are called equivalence classes. Good enough not difficult. But in the example where

A = {1, 2, 3, 4} and define a relation R by: xRy <-> x + y is even.

The relation is equivalence relation. R = {(1, 1), (1, 3), (3, 3), (3, 1), (2, 2), (4, 4), (4, 2)}
and they say equivalence classes : {1, 3} and {2, 4}

This i can not understand.. why only these two? doesn't {1 ,1} {2, 2} {3, 3} {4, 4} counted?

Set theory is too hard..I thought i understood everything and when i look back everything is new! well that must be because i couldn't have enough time for revision but this is too much.

Any definitions of empty relation and equivalence class that can be understood by person like me?

Homework Helper
A relation R in a set is a set of ordered pairs, so any subset of a set of ordered pairs will be a relation. This includes the empty set which is referred to as the empty relation.

What is this mean? empty set = empty relation?

If X is a set with an equivalence relation R, then R is a relation on any subset of X, including the empty set

and if so then why empty relation is symmetric as well as transitive? My teacher said it is done by default but i still can not understand it.

The rules for an equivalence relation say things like 'R satsifies: for all x in X...'. Well, if we let X be the empty set then 'for all x in X' is always false, and any implication of the form False => True is true. So the empty set with any relation is an equivalence relation, but it has no equivalence classes, and is very boring. But it makes the statement of the theorems easier - it is generally better to allow the empty set to be a trivial example, rather than make statements like : for all subsets of X except for the empty set.

In case of equivalence class i understand the concept and i thought it was easy. An equivalnce relation on Set partitions Set into subsets which are called equivalence classes. Good enough not difficult. But in the example where

A = {1, 2, 3, 4} and define a relation R by: xRy <-> x + y is even.

The relation is equivalence relation. R = {(1, 1), (1, 3), (3, 3), (3, 1), (2, 2), (4, 4), (4, 2)}

Note these are elements of AxA.

and they say equivalence classes : {1, 3} and {2, 4}

and these are subsets of A - you just have to amalgamate all of the elements of A that are related by the relation, i.e. (1,1) (1,3) (3,1) and (3,3) show that the equivalence class containing 1 is {1,3} a subset of A.

This i can not understand.. why only these two? doesn't {1 ,1} {2, 2} {3, 3} {4, 4} counted?

because you're confusing (1,1) as an element of AxA with the symbol {1,1} which isn't allowed as sets don't have repeated elements.

In general I would never teach that an equivalence relation is a subset of AxA satsifying... because it is completely unhelpful and unnecessary.

An equivalence relation should just be defined like '=', cos that is all it is.

Homework Helper
Here are some simple examples.

We'll say that x~y if 2 divides x-y. What are the equivalence classes? They are the odd integers and the even integers. We can choose a representative of each:  and  would seem to be good candidates.

What about the real numbers R. I'll say that x~y if x-y is an integer, i.e. if x and y have the same fractional part. Is there a good candidate for each equivalence class now? Yes there is - since two things are equivalent if and only if their fraction parts are the same, consider the set

[0,1) = { x : 0<= x < 1}

this forms a complete set of the representatives of equivalence classes.

385sk117
Ohhhhhh I got it know! so R={()} things are the element of AxA and the subsets of A{1, 2, 3, 4} are {1, 3} and {2, 4} as repeated elemtns are not allowed.

But in the explanation of empty set i can not understand this line
and any implication of the form False => True is true
Sorry my english is not good enough; maybe this is related to the vacuous truth right?

Anyways thankyou very much for your explanation it really helped me a lot :)

Homework Helper
If X is a set with an equivalence relation R, then R is a relation on any subset of X, including the empty set

Matt, I don't think that's what the OP was referring to! The empty relation is when the *relation* itself is empty, not when the set it operates on is empty. So for the set {1, 2} the relation ~ that has
1 ~ 1
1 ~ 2
2 ~ 1
2 ~ 2
as false is the empty relation on {1, 2}. By comparison, the operator < has
1 < 2
true and
1 < 1
2 < 1
2 < 2
false.

Formally the relation < would be defined (on the set {1, 2}) as {(1, 2)} and the empty relation would be defined as {}. = on the same set could be defined as {(1, 1), (2, 2)}.

A relation is symmetric if for every a ~ b you have b ~ a. For the empty relation a ~ b is always false, so the empty relation is always symmetric. Similarly, if you apply the definitions you'll see that the empty relation is always associative, transitive, and antisymmetric. The empty relation is reflexive only over the empty set. For example, the empty relation over {1, 2} is not reflexive because 1 ~ 1 is not true. But the empty relation over {} is reflexive (because being reflexive over {} doesn't require anything!).

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Homework Helper
Thanks for clearing that up, CR, but what you said apparently contradicts what the OP's teacher is reported to have said about it being transitive. (I've never heard of the empty relation, and was taking the only logical definition given the original post in order to make an equivalence relation, which was probably a silly thing to do. The empty relation of course is not an equivalence relation as you point out except in the trivial case.)

Homework Helper
Thanks for clearing that up, CR, but what you said apparently contradicts what the OP's teacher is reported to have said about it being transitive.

The empty relation is transitive, though. Being transitive means that if a ~ b and b ~ c, then a ~ c. But the first condition never holds, so the empty relation is always transitive.

The empty relation isn't reflexive (except over the empty set, as I mentioned), but that's not a problem -- the OP's teacher didn't claim that the empty relation was an equivalence relation, just symmetric and transitive.

385sk117: Understanding equivalence relations can be tricky, since it requires you to learn new concepts and hold them all in your mind at the same time without confusing them with other ones. The empty relation easy -- maybe the easiest thing. It only seems hard because you're looking for something hard.

You can think of a relation like this: you give it two things (in order), and it tells you if they're related. You say 1 and 10, and "<" tells you "They're related, 1 < 10"; you say 3 and 2 and "<" tells you "They're not related, 3 < 2 is false". In that case the empty relation is the one that is stuck in the 'no' mode, "Not related".