Encountered a WEIRD vertex-form equation

[AznBoi]

Ok the equation: y=(x-1)^2

How come it has a y intercept of (0,1) but the equation does not have a
+1 at the end of it??

I thought all y-intercepts are at the end of the vertex-form equation.

 

[courtrigrad]

$$y = a(x-p)^{2} + q$$ where $$(p,q)$$ are the coordinates of the vertex. You are thinking of $$y=mx+b$$ where $$b$$ is the y-intercept.

 

[AznBoi]

Lol, yeah that's it. So only the equation of the line has the y-intercept in it. The h,k is only the vertex, k is not the y-intercept right?

 

[bob1182006]

k is the y-intercept, h is the x-intercent in the form $y=a(x-h)^{2}+k$

 

[courtrigrad]

no its not. So if you have $$y = (x-2)^{2} + 6$$ your saying 2 is the x-intercept, and 6 is the y-intercept?