# Encountered a WEIRD vertex-form equation

1. Oct 9, 2006

### AznBoi

Ok the equation: y=(x-1)^2

How come it has a y intercept of (0,1) but the equation does not have a
+1 at the end of it??

I thought all y-intercepts are at the end of the vertex-form equation.

2. Oct 9, 2006

$$y = a(x-p)^{2} + q$$ where $$(p,q)$$ are the coordinates of the vertex. You are thinking of $$y=mx+b$$ where $$b$$ is the y-intercept.

3. Oct 9, 2006

### AznBoi

Lol, yeah thats it. So only the equation of the line has the y-intercept in it. The h,k is only the vertex, k is not the y-intercept right?

4. Oct 10, 2006

### bob1182006

k is the y-intercept, h is the x-intercent in the form $y=a(x-h)^{2}+k$

5. Oct 10, 2006

no its not. So if you have $$y = (x-2)^{2} + 6$$ your saying 2 is the x-intercept, and 6 is the y-intercept?