Encountered a WEIRD vertex-form equation

  • Thread starter Thread starter AznBoi
  • Start date Start date
  • Tags Tags
    Weird
Click For Summary

Homework Help Overview

The discussion revolves around understanding the vertex form of a quadratic equation, specifically the equation y=(x-1)². Participants are exploring the relationship between the vertex form and the y-intercept, questioning how the y-intercept can be determined from the equation without a constant term added at the end.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the distinction between the vertex form of a quadratic equation and the slope-intercept form. Questions are raised about the roles of the parameters in the vertex form and their relation to the y-intercept.

Discussion Status

The discussion is active, with participants providing insights into the definitions of the vertex form and the slope-intercept form. There is some confusion regarding the interpretation of the parameters, particularly in relation to the y-intercept and x-intercept, indicating a productive exploration of the topic.

Contextual Notes

Participants are grappling with the definitions and implications of the vertex form parameters, particularly in the context of homework constraints that may limit their exploration of these concepts.

AznBoi
Messages
470
Reaction score
0
Ok the equation: y=(x-1)^2

How come it has a y intercept of (0,1) but the equation does not have a
+1 at the end of it??

I thought all y-intercepts are at the end of the vertex-form equation.
 
Physics news on Phys.org
[tex]y = a(x-p)^{2} + q[/tex] where [tex](p,q)[/tex] are the coordinates of the vertex. You are thinking of [tex]y=mx+b[/tex] where [tex]b[/tex] is the y-intercept.
 
Lol, yeah that's it. So only the equation of the line has the y-intercept in it. The h,k is only the vertex, k is not the y-intercept right?
 
k is the y-intercept, h is the x-intercent in the form [itex]y=a(x-h)^{2}+k[/itex]
 
no its not. So if you have [tex]y = (x-2)^{2} + 6[/tex] your saying 2 is the x-intercept, and 6 is the y-intercept?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K