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Encountered a WEIRD vertex-form equation

  1. Oct 9, 2006 #1
    Ok the equation: y=(x-1)^2

    How come it has a y intercept of (0,1) but the equation does not have a
    +1 at the end of it??

    I thought all y-intercepts are at the end of the vertex-form equation.
  2. jcsd
  3. Oct 9, 2006 #2
    [tex] y = a(x-p)^{2} + q[/tex] where [tex] (p,q) [/tex] are the coordinates of the vertex. You are thinking of [tex] y=mx+b [/tex] where [tex] b [/tex] is the y-intercept.
  4. Oct 9, 2006 #3
    Lol, yeah thats it. So only the equation of the line has the y-intercept in it. The h,k is only the vertex, k is not the y-intercept right?
  5. Oct 10, 2006 #4
    k is the y-intercept, h is the x-intercent in the form [itex]y=a(x-h)^{2}+k[/itex]
  6. Oct 10, 2006 #5
    no its not. So if you have [tex] y = (x-2)^{2} + 6 [/tex] your saying 2 is the x-intercept, and 6 is the y-intercept?
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