1. The power radiated by the sun is 3.9 x 10^26 W. The earth orbits the sun in a nearly circular orbit of radius 1.5 x 10^11 m. The earth's axis of rotation is tilted by 27 degrees relative to the plane of orbit, so sunlight does not strike the equator perpendicularly. What power strikes a 0.75-m^2 patch of flat land at the equator? 2. Relevant equations S(Intensity) = Power/Area S2 = S1 x cos^2 (delta theta) Surface area = 4pi x radius^2 (maybe?) 3. The attempt at a solution Surface area using the radius 1.5 x 10^11m and got A=2.83 x 10^23 Next, i used S = Power/Area using the power of the sun and the area and got 1379W/m^2 Then, I used S2=S1 x cos^2( theta) and got 118W/m^2 Finally, I used S=P/A again but with the patch of flat land area and got a final answer of 88W The answer is 920W so if someone could go over this with me I'd greatly appreciate it!