Energy conservation in circular motion

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SUMMARY

The discussion focuses on calculating the normal force acting on a 1 kg object moving along a circular frictionless path with a radius of 0.5 m at an angle of 30° from the vertical. The correct calculation reveals that the normal force at point B is 25.98 N. Participants corrected initial mistakes in the energy conservation equation, specifically the misapplication of variables and the height calculation at point B. The final consensus confirms the answer as 25.98 N.

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  • Basic algebra for solving equations
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Fatima Hasan
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Homework Statement


An object of mass m = 1 kg moves along a circular frictionless path of radius R = 0.5 m from point A to point B at which it makes an angle θ with the vertical direction as shown in the figure. If the object is release from rest (VA = 0) and θ = 30° , what is the normal force at point B (in N) ?
upload_2018-1-6_16-25-52.png


A ) 2.98 B) 25.98 C) 28.19 D) 29.54

Homework Equations


gif.gif


3. The Attempt at a Solution [/B]
Here's my work :
%5CF%3Dma%5C%5CF%3D2.67%20N%5C%5Cmg%20cos%20%5CTheta%20-FN%3D2.67%5C%5C8.6-FN%3D2.67%5C%5CFN%3D5.gif
 

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  • %5CF%3Dma%5C%5CF%3D2.67%20N%5C%5Cmg%20cos%20%5CTheta%20-FN%3D2.67%5C%5C8.6-FN%3D2.67%5C%5CFN%3D5.gif
    %5CF%3Dma%5C%5CF%3D2.67%20N%5C%5Cmg%20cos%20%5CTheta%20-FN%3D2.67%5C%5C8.6-FN%3D2.67%5C%5CFN%3D5.gif
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Fatima Hasan said:

Homework Statement


An object of mass m = 1 kg moves along a circular frictionless path of radius R = 0.5 m from point A to point B at which it makes an angle θ with the vertical direction as shown in the figure. If the object is release from rest (VA = 0) and θ = 30° , what is the normal force at point B (in N) ?
View attachment 217967

A ) 2.98 B) 25.98 C) 28.19 D) 29.54

Homework Equations


View attachment 217968

3. The Attempt at a Solution [/B]
Here's my work :
View attachment 217969
Your work is wrong. What is k?
You can not write gh=gh+0.5v^2. It means that the v2=0.
 
ehild said:
Your work is wrong. What is k?
You can not write gh=gh+0.5v^2. It means that the v2=0.
K is a typo. It should be m
gh1 = gh2 + 0.5 v^2
 
Fatima Hasan said:
K is a typo. It should be m
gh1 = gh2 + 0.5 v^2
It is better now, but your v2is wrong.
 
ehild said:
It is better now, but your v2is wrong.
I found the mistake. The height in B, I should substract it from 0.5
The answer is 25.98
 
Fatima Hasan said:
I found the mistake. The height in B, I should substract it from 0.5
The answer is 25.98
Well done!
 
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