Energy Conserved in momentum problem

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Homework Help Overview

The problem involves a 4.0 kg bowling ball colliding elastically with another 4.0 kg ball at rest. The original poster seeks to determine the velocity of the second ball post-collision, assess the nature of the collision, and evaluate energy conservation during the event.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply conservation of momentum and energy principles but expresses uncertainty about how to determine if the collision is perfectly elastic and how to assess energy conservation.
  • Participants discuss relevant equations for energy and explore the concept of energy conservation in elastic collisions.
  • Some participants suggest calculating kinetic energy before and after the collision as a means to evaluate energy conservation.

Discussion Status

Participants are actively engaging with the problem, sharing equations and reasoning about energy conservation. There is a suggestion to compare kinetic energy before and after the collision, and some participants express confidence in the idea that energy is conserved in elastic collisions.

Contextual Notes

There is a note that potential energy is typically not relevant in collision problems involving hard particles unless specific conditions apply, which may influence the discussion on energy conservation.

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Homework Statement


A 4.0kg bowling ball rolling to the right at 8.0 m/s has an elastic head-on collision with another 4.0kg ball initially at rest. The first ball stops after the collision.
a) Find the velocity of the canoe after the collision?
b) Is the collision perfectly elastic? (show work)
c) Is energy conserved? (show work)

Homework Equations


m1v1+m2v2 = m1v1' + m2v2'
PE=KE
mgh=1/2mv2

The Attempt at a Solution


a) (4.0kg)(8.0m/s) + (4.0kg)(0 m/s) = (4.0kg)(0 m/s) + (4.0kg)(v2')
32 kgm/s + 0 kgm/s = 0 kgm/s + 4.0kg(v2')
8 m/s = v2'

b) Don't know how to tell if it is perfectly elastic, no equation that I can think of

c) Don't know how to tell if energy is conserved, no equation that I can think of
 
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What equations do you know of that deals with energy?
 
I know KE = PE, and that is 1/2 mv2 = mgh
 
So we know that in an elastic collision, energy is conserved, right? So is there a way to compare the before and after collision energy?
 
I do know that no energy is lost, so that means energy is conserved. As to a way to compare the before and after collision energy..I'm sifting through my notes and not seeing anything glaring out.
 
Well, you could calculate the energy of the system before and after, right?

Hint: Kinetic energy.
 
.5(4.0kg)(8.0m/s)2 = 128 J = .5(4.0kg)(8.0 m/s)2

oh...so the KE is the same on both sides, so no energy is lost.

and if no energy is lost, then it has to be perfectly elastic?
 
Yup, simple as that!
 
Woopy said:

Homework Statement


A 4.0kg bowling ball rolling to the right at 8.0 m/s has an elastic head-on collision with another 4.0kg ball initially at rest. The first ball stops after the collision.

Homework Equations


m1v1+m2v2 = m1v1' + m2v2'
PE=KE
mgh=1/2mv2
You should also be aware that PE has nothing to do with this problem. Typically, you don't consider PE in collision problems between hard particles (eg. bowling balls), gravitational or otherwise. An exception would be if the balls were rolling on a slanted surface, or if a ball collides with a spring, but usually you just ignore PE in a collision problem.
 

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