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Showing all working Calculate the total energy expanded in the acceleration;

S=(.5)at^2

5=(.5)a(0.92^2)

=0.4232 a

a=5/0.4232 = 11.8147 ms^2

V=at

=11.8147*0.92

=10.8695 ms^-1

s=(.5)a(t^2)

s=4.999 m

Work done;

W=F*d=80*5= 400J

Power;

W=P*t

P=W/t=400/0.92=434.78 watt

The final velocity of the mass

Vf^2=Vi^2+2ad (vi=0, as the mass is initially at rest)

F=m*a

a=F/m=80/6=13.33 m/s^2

Vf^2=2*13.33*5=133.33

Vf=11.55m/s

the final momentum

p=mv

=6*11.55=69.3 N/s

the final kinetic energy

K=0.5*m*v^2=533 J

Have I answered the fundamental points of the question of is there irrelevant things I could remove, I'm just trying to answer the question as thoroughly and best I can..thanks