Understanding Partial Derivatives: A Visual Explanation

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SUMMARY

This discussion focuses on the concept of partial derivatives, particularly in the context of a PHY101 course. Participants clarify that when differentiating a function with multiple variables, such as xyz with respect to y, the other variables (x and z) are treated as constants. The discussion emphasizes that this approach mirrors the principles of regular derivatives learned in Calculus 1, where constants are replaced with variables. Visual aids, such as diagrams, are recommended to enhance understanding of partial derivatives.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically derivatives.
  • Familiarity with functions of multiple variables.
  • Knowledge of how to treat constants in differentiation.
  • Ability to interpret mathematical notation and expressions.
NEXT STEPS
  • Study the concept of partial derivatives in multivariable calculus.
  • Learn how to visualize functions of multiple variables using graphical representations.
  • Explore the application of partial derivatives in physics, particularly in mechanics.
  • Review the chain rule and its relevance to partial differentiation.
USEFUL FOR

Students in introductory physics courses, particularly those struggling with calculus concepts, educators teaching multivariable calculus, and anyone seeking to understand the application of partial derivatives in real-world scenarios.

O.J.
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OK, they're throwing pretty weird concepts to our heads in this PHY101 course. stuff like even partial derivatives that we didnt take in math. differentiating partially with respect to a single variable treating others as contants is NOT getting through my head. can someon PLEASE illustrate it for me?
 
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partial derive of xyz with respect to y (say) is as if z and x are just numbers
so you get xz*1= xz.

Say you replaced every other variable with a fixed number except the var. you differentiate. It is then just regular derivatives. Remember calc 1? What is the deriv. (w/ resp. to x) of Cx^4 ...ANS> C*4*x^3. Now, change C to another variable y,z,w ...whatever.. same math.

Hope it helps.
 
<br /> E_p(k_X, k_Y) = \iint E_s(x,y)e^{i(xk_X+yk_Y)}\,dx\,dy<br />
 
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heh, wish I knew what text you were using, I was looking for a phy101 that does exactly this(but that it does it without warning you before you enroll is pretty nasty)
 
gammamcc said:
partial derive of xyz with respect to y (say) is as if z and x are just numbers
so you get xz*1= xz.

Say you replaced every other variable with a fixed number except the var. you differentiate. It is then just regular derivatives.


Remember calc 1? What is the deriv. (w/ resp. to x) of Cx^4 ...ANS> C*4*x^3. Now, change C to another variable y,z,w ...whatever.. same math.

Hope it helps.

pretty sure he doesn't get the concept but he knows how to do it.

It's like the derivative wrt x (say) along a curve where z,y are constant. Drawing a picture will make it easy straight away. Think of a solid shape. Chop it into two pieces. The rate of change along the edge is kind of doing a partial derivative.
 

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