Energy in circular path with spring

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SUMMARY

The discussion focuses on a spring-mass system constrained to move along a circular path with a radius R. The user seeks to calculate the velocity at point A when the spring is released from point B, utilizing the equation for conservation of energy: potential energy of the spring plus gravitational potential energy equals kinetic energy. Additionally, the user inquires about the necessary spring constant to prevent the mass from reaching point C, which is determined by equating the spring's potential energy to the kinetic energy at point B.

PREREQUISITES
  • Understanding of Hooke's Law and spring potential energy (½*k*Δx²)
  • Knowledge of gravitational potential energy (m*g*R)
  • Familiarity with kinetic energy (½*mv²)
  • Basic principles of circular motion and geometry
NEXT STEPS
  • Explore the derivation of energy conservation in spring-mass systems
  • Learn about the relationship between spring constant and oscillation frequency
  • Investigate the effects of varying spring constants on motion in circular paths
  • Study the application of geometry in determining displacement in spring systems
USEFUL FOR

Students and professionals in physics, mechanical engineering, and anyone interested in dynamics of spring systems and circular motion analysis.

edowuks
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We have a spring that has equilibrium at distance R. the spring is attached at horizontal distance R from circle (R is distance from edge of circle, distance from circles origo is 2R) that has radius R. Mass attached to spring can move freely in that circle path. In circle we have 3 points a=point where spring is at rest. B=at angle pi/2 C=opposite side of spring than the point a. (sorry I don't have picture and my english is bad).
A) calculate velocity at point a when spring is released from point b (at picture we have on paper we can see that at point b it has gravitational potential energy of mgR)
B) How height should the spring constant be that mass never reachess point c

Ok I have banged my head to wall two days, I cannot figure what should I calculate here. Can I just calculate the A part by 'potential of spring'+mgR=½mv² (can potential of spring be calculated from length of pring-R). B-part I don't understand what should I calculate, but with my poor explanation I think no-one can give any hint?

I don't need anykind of solution just hint what I should be calculating, can't picture the problem in my head.
 
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edowuks said:
We have a spring that has equilibrium at distance R. the spring is attached at horizontal distance R from circle (R is distance from edge of circle, distance from circles origo is 2R) that has radius R. Mass attached to spring can move freely in that circle path. In circle we have 3 points a=point where spring is at rest. B=at angle pi/2 C=opposite side of spring than the point a. (sorry I don't have picture and my english is bad).
A) calculate velocity at point a when spring is released from point b (at picture we have on paper we can see that at point b it has gravitational potential energy of mgR)
B) How height should the spring constant be that mass never reachess point c

Ok I have banged my head to wall two days, I cannot figure what should I calculate here. Can I just calculate the A part by 'potential of spring'+mgR=½mv² (can potential of spring be calculated from length of pring-R). B-part I don't understand what should I calculate, but with my poor explanation I think no-one can give any hint?

I don't need anykind of solution just hint what I should be calculating, can't picture the problem in my head.

The potential in your spring is = ½*k*Δx2 and as you point out that plus drop in height m*g*R will result in your ½*mv2.

Your Δx here can be found by ordinary geometry.

For part 2 you know the KE at b so for the mass to make it to c, which by your description is at the same level as b then there is no need to account for any change in potential energy, so ½*k*(2R)2 = the KE when it was at b.
 
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