Energy losses in cables: What is the ohmic loss?

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Discussion Overview

The discussion revolves around calculating the ohmic losses in electrical cables with specific parameters, including cross-sectional area, voltage, maximum power, length, and resistivity. The focus is on the application of formulas related to electrical resistance and power loss.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents a scenario involving two cables and seeks to calculate the ohmic loss using the formula P(ohmic) = R(cable) x I^2.
  • Another participant requests clarification on the calculations attempted and notes that the current (I) is not provided in the original question.
  • A participant expresses confusion about the calculations, indicating that the calculated ohmic power exceeds the maximum power, which raises concerns about the validity of the approach used.
  • There is a suggestion to clarify the use of formulas, specifically questioning whether the participant used V^2/R instead of V^2R.
  • Participants encourage showing actual calculations for better assistance.

Areas of Agreement / Disagreement

The discussion remains unresolved, with participants expressing confusion and seeking clarification on the calculations without reaching a consensus on the correct approach or values.

Contextual Notes

There are limitations regarding the provided information, particularly the absence of the current value, which is crucial for calculating the resistance and subsequent power loss accurately.

Suziii
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having 2 cables of 790 mm^2 cross sectional area and voltage of 450 kV. the maximum power is 700 MW and the length of cables 580 km. Assuming the resistivity of the conductor is 1.67microohmcm. then what is the ohmic lose?

Thanks in advance
 
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Welcome to PF!

Hi Suziii! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Thanks a lot.

I tried to find the ohmic power by the following formula: P(ohmic)=R (cable) x I^2 where R is the resistance and I the current.Then I divided the value for P (ohmic) and for P (max). however the problem is that by doing this I am getting higher value for P (ohmic) than for P (max) which should not be the case.
 
Hi Suziii! :smile:

(have an ohm: Ω and a mu: µ and try using the X2 icon just above the Reply box :wink:)
Suziii said:
I tried to find the ohmic power by the following formula: P(ohmic)=R (cable) x I^2 where R is the resistance and I the current.Then I divided the value for P (ohmic) and for P (max). however the problem is that by doing this I am getting higher value for P (ohmic) than for P (max) which should not be the case.

I don't understand … I isn't given in the question :confused:

(did you use V2R instead of V2/R ?)

anyway, please show your actual calculations in future :wink:
 

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