Energy of a solid rotating sphere

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SUMMARY

The energy of a solid rotating sphere with uniform mass density ρ and radius R, rotating with angular velocity ω(t), is calculated using the integral E = ∫ ρ v²(r) d³r. The correct expression for the energy derived from the integration is E = (2/5) M R² ω², where M is the mass of the sphere. The initial attempt mistakenly suggested E = (3/5) M R² ω², which was corrected by referencing the moment of inertia formula.

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wduff
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Homework Statement



A system of particles, forming a sphere of uniform mass density \rho and radius R, rotates around the axis of the sphere with angular velocity omega(t) calculate the energy of the system.

Homework Equations



we were told to solve the problem with this integral:

E = \int \rho v2 (r) d3r

The Attempt at a Solution



I took \rho = M/( 4/3 \pi R3)

v3 = r2 \omega2

and d3 r = r^2 sin \theta dr d\phi d\theta

integrating from 0 to R for r, from 0 to pi for theta, and from 0 to 2 pi for phi, I got

3/5 M R^2 \omega^2

I think the answer ought to be 1/5 MR^2 w^2, right? Thanks for the help.
 
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Hi wduff! Welcome to PF! :smile:

(have a pi: π and an omega: ω and a theta: θ and a phi: φ and a rho: ρ and try using the X2 tag just above the Reply box :wink:)

You've used v = ωr, but it's not the same r, is it? :wink:

(and it's 2/5 … see http://en.wikipedia.org/wiki/List_of_moments_of_inertia)
 
Aha! Thanks a ton tiny tim! And yeah sorry about the terrible formatting I'm sure I'll get the hang of it.
 

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