Energy Problem involving Spring

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SUMMARY

The discussion centers on a physics problem involving a 1.0 kg block attached to two springs, A and B, with respective forces of 10.0 N and 2.5 N required to stretch them by 0.25 m. The total work done to move the block 0.50 m is calculated as 6.25 J. The problem also explores the velocity of the block as it passes through the equilibrium position and the equivalent spring constant that would replicate the effects of both springs combined. Key equations include work done (W = FΔd) and energy equations for springs and kinetic energy.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with the work-energy principle
  • Knowledge of kinetic and potential energy equations
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of spring potential energy and its derivation
  • Learn about the integration of force over distance for variable forces
  • Explore the conservation of mechanical energy in spring systems
  • Investigate the relationship between mass, spring constants, and oscillation frequency
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Students studying physics, particularly those focusing on mechanics and energy systems, as well as educators seeking to enhance their understanding of spring dynamics and energy conservation principles.

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Homework Statement


A block of mass 1.0 kg, at rest on a horizontale table, is attached to two rigid supports by springs A and B. A force of 10.0 N strecthes spring A alone by 0.25 m while a force of 2.5 N extends spring B alone by the same amount. Initially the block is at rest between unstretched springs; then it is pushed to the side a distance of 0.50 m, compressing one spring and extending another.

a) What is the total work done to move the block. (The block is held at rest.)
b) If the block is released with what velocity does it move through its original equilibrium position?
c) What would be the spring constant of a single spring that would duplicate A and B?

mass of block = 1.0 kg
Force to stretch spring A by 0.25 m = 10.0 N
Force to stretch spring B by 0.25 m = 2.5 N
side distance pushed = .5 m

Homework Equations


W = FΔd
Ee = 1/2kx^2
Ek = 1/2mv^2

The Attempt at a Solution


a) W = Fd
= (10 + 2.5)(0.5)
= 6.25 J

b) Not sure how to do this I think it has something to do with the energy but not sure exactly what it's asking for. From what I understood it'd be something like

1/2(k1)x^2 + 1/2(k2)x^2 + 1/2mv^2 = 1/2(k1)x^2 + 1/2(k2)x^2
 
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testme said:
a) W = Fd
= (10 + 2.5)(0.5)
= 6.25 J
The force produced by a spring does not remain constant with distance. So you'll either have to integrate F*dx or use the 'canned' expression for spring potential energy.

It happens to be a fluke of the numbers for this problem that your 'method' above gives the same result as the correct methods.
b) Not sure how to do this I think it has something to do with the energy but not sure exactly what it's asking for. From what I understood it'd be something like

1/2(k1)x^2 + 1/2(k2)x^2 + 1/2mv^2 = 1/2(k1)x^2 + 1/2(k2)x^2
Something like that :smile:

What's the total energy that system holds? Give it a name (say, E).

When the block is at the equilibrium position, how much potential energy is in the springs? Where must the rest be?
 

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