Energy Problem (Systems and Energy Conversion)

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SUMMARY

The discussion focuses on calculating the optimal height for a parachute to be deployed to achieve a final speed of 5.00 m/s for an 80.0 kg parachutist jumping from a height of 1,000 m. The constant retarding force is 50.0 N before the parachute opens and 3,600 N once it is deployed. Utilizing the equations for kinetic energy (KE = 1/2 mv²), potential energy (PE = mgy), and work (W = Fd), participants analyze the energy conversion and forces acting on the parachutist to determine the required height for parachute deployment.

PREREQUISITES
  • Understanding of kinetic energy and potential energy concepts
  • Familiarity with the equations of motion and forces
  • Knowledge of basic physics principles related to energy conversion
  • Ability to perform calculations involving mass, force, and height
NEXT STEPS
  • Study the principles of energy conservation in physics
  • Learn about the effects of drag force on falling objects
  • Explore advanced topics in dynamics, such as terminal velocity
  • Investigate real-world applications of parachute physics in aerospace engineering
USEFUL FOR

Physics students, aerospace engineers, and anyone interested in the dynamics of free fall and parachute deployment.

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Homework Statement


At what height should a parachute be opened so the final speed is 5.00 m/s. (The parachuter is 80.0 kg. He jumps off a balloon at 1,000 m. The total retarding force on the man is constant at 50.0 N with the parachute closed and constant at 3,600 N with the parachute open.)


Homework Equations


Kinetic Energy --- KE=1/2mv2
Potential Energy --- PE=mgy ... g=9.8 m/s2
Work --- W=Fd


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