Energy Required to Change Water into Steam

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SUMMARY

The energy required to change one-quarter of 8.0 kg of water at 25°C into steam is calculated to be 7.12 x 10^6 J. This calculation involves two steps: first, heating the entire 8.0 kg of water from 25°C to 100°C using the specific heat capacity of water (4200 J/kg°C), and then converting 2.0 kg of that water into steam using the latent heat of vaporization (2.3 x 10^6 J/kg). The calculations confirm that the methodology and results are accurate.

PREREQUISITES
  • Understanding of specific heat capacity and its formula
  • Knowledge of latent heat of vaporization
  • Basic algebra for energy calculations
  • Familiarity with temperature units (Celsius)
NEXT STEPS
  • Study the principles of thermodynamics related to phase changes
  • Learn about specific heat capacity calculations in different materials
  • Explore the concept of latent heat in various substances
  • Investigate practical applications of steam generation in engineering
USEFUL FOR

Students studying physics or chemistry, educators teaching thermodynamics, and professionals in engineering fields focused on heat transfer and energy calculations.

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Homework Statement



How much energy is required to change one-quarter of 8.0kg of water at 25 C into steam?

The way I see it, the entirety of the 8.0kg of water must be brought from 25 C to 100 C, then only 2.0kg is changed to steam so...

Specific heat capacity (of water) = 4200 J / kg C
Latent heat of vaporization (of water) = 2.3 * 10^6 J/kg

Q total = (8.0kg) (4200 J / kg C) (100-25) + (2.0kg) (2.3 * 10^6 J/kg)
Q total = 7.12 * 10^6 J

I'm not 100% sure if I'm doing this properly. Does this look correct?
 
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That looks correct to me!
 
Cool, thanks!
 

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