- #1

LonelyElectron

- 18

- 1

## Homework Statement

A container holds 8.0 kg of water at 25 ˚C. How much energy must be added to the water to create 2.0 kg of steam?

## Homework Equations

To be honest, not sure. SO MANY equations were given, and I don't know what is a variation of what.

## The Attempt at a Solution

Q_total = Q_warm water + Q_boil water

=mc_wt+m_sL_v

= (8.0 kg)(4200 J/(kg* degrees C))(100 degrees C - 25 degrees C)+(2.0 kg)(2.3x10^6)

=2520000 J + 4600000 J

=7120000 J

=7.1 x 10^6 J

Therefore 7.1 x 10^6 J of heat energy have to be added to the water to create 2.0 kg of steam.

Does that make any sense?