- #1
LonelyElectron
- 18
- 1
Homework Statement
A container holds 8.0 kg of water at 25 ˚C. How much energy must be added to the water to create 2.0 kg of steam?
Homework Equations
To be honest, not sure. SO MANY equations were given, and I don't know what is a variation of what.
The Attempt at a Solution
Q_total = Q_warm water + Q_boil water
=mc_wt+m_sL_v
= (8.0 kg)(4200 J/(kg* degrees C))(100 degrees C - 25 degrees C)+(2.0 kg)(2.3x10^6)
=2520000 J + 4600000 J
=7120000 J
=7.1 x 10^6 J
Therefore 7.1 x 10^6 J of heat energy have to be added to the water to create 2.0 kg of steam.
Does that make any sense?