- #1

sallychan

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## Homework Statement

100 g of steam at 100 °C is mixed with 500 g of water at 25 °C. What is the final temperature of the mixture?

## Homework Equations

Q= mL

Q= mcΔT

## The Attempt at a Solution

Heat given by to water = heat loss at condensation

= mLv

= (0.1) (2.26 E 6)

= 226000 J

Maximum possible heat water can take = mc ΔT

= (0.5) (4186)(100-25)

= 156975 J

Because water does not take up all the latent heat from steam, only some of the steam condensate.

I wonder is my conclusion right? Or will latent heat given by steam actually boils water?

Thanks!

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