Energy required to move an object in orbit?

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To calculate the energy required to boost the International Space Station (ISS) from an orbit of 335 km to 352 km, the gravitational potential energy (Ep) at both heights must be determined using the formula Ep = GMm/r. Initial and final distances from Earth's center are calculated, and the potential energies are found to be approximately 2.316682247E13 J and 2.316676064E13 J, respectively. The difference in potential energy is approximately 6.2 x 10^7 J, but this calculation does not account for the kinetic energy associated with the orbital speeds at each height. The total energy (Et) must include both potential and kinetic energy, as the speed of the ISS is a function of its orbital height. The difference in total energy will provide the minimum energy required to boost the ISS to its new orbit.
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The International Space Station, with a mass of 370,000 kg, is orbiting the Earth at a height 335 km and needs to be boosted to an orbit of 352 km. Calculate the energy needed to boost the ISS to its new height.

m = 370,000 kg
M = 5.98 x 10^24 kg
G = 6.67 x 10^-11 Nm^2/kg^2
Initial distance from Earth's center = (6.38 x 10^6m) + 335000m
Final distance form eath's center = (6.38 x 10^6m) + 352000m


Using Ep = GMm/r

I calculated
Epi = (6.67x10^-11)(5.98x10^24)(370000)/((6.38x10^6)+(335000)) = 2.316682247E13

and

Epf = (6.67x10^-11)(5.98x10^24)(370000)/((6.38x10^6)+(352000)) =2.316676064E13

I found the difference of the two, and took it as my answer, 6.2x10^7 J

I feel I'm doing something wrong, Thanks in advance for any help!
 
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Have you considered the difference in speed (and so Kinetic energy) for the two orbits?
 
mgb_phys said:
Have you considered the difference in speed (and so Kinetic energy) for the two orbits?

Hmmm, so I would have to find the total energy,

Et = Ep + Ek = G Mm/r + .5mv^2

ok I think I got it now.
 
Remember that V is also a function of r and M (there is a fixed speed for each orbital height)
 
mgb_phys said:
Remember that V is also a function of r and M (there is a fixed speed for each orbital height)

yes, v = sqrt(MG/r)

so figuring out the difference in total energy, would that give me the amount of energy needed to boost the space station to its new height?
what I mean is, does difference in total energy = amount of energy required to boost to new height?
 
Yes actualy that's the minimum energy, assuming you want it to orbit in the same direction
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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