Gravitational potential energy, orbital speed, binding energy.

  • #1
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Homework Statement


a satellite having a mass of 1800 kg orbits the earth at a distance of 6.3 x 10^5 m above the surface find the gravitational potential energy of the satellite while in orbit, the orbital speed and the binding satellite.

The Attempt at a Solution



gravitational potential energy
Eg = -GMm/Ro
Eg = -(6.67x10^-11 Nm^2/kg^2)(5.98x10^24kg)(1800kg)/(6.37x10^6m)+(6.3x10^5m)
Eg = -1.03 x 10^11 J

the orbital speed

Ek = 1/2(GMm/Ro)
Ek = 0.5 x -1.03 x 10^11 J
Ek = 5.128277145 x 10^10 J

Ek = 1/2mv^2
V = 7548.57 m/s

binding satellite
Eb = 1/2(GMm/Ro)
Eb = 0.5 x -1.03 x 10^11 J
Eb = 5.128277145 x 10^10 J
 

Answers and Replies

  • #2
haruspex
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the orbital speed
Ek = 1/2(GMm/Ro)
Whilst that is true, I would prefer to use the equivalence of the gravitational force and the centripetal force required to maintain the orbit. That seems to me to be a more fundamental principle.
binding satellite
Eb = 1/2(GMm/Ro)
I'm not sure about that. Does binding energy take into account the KE? Maybe it does.
 
  • #3
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Whilst that is true, I would prefer to use the equivalence of the gravitational force and the centripetal force required to maintain the orbit. That seems to me to be a more fundamental principle.

I'm not sure about that. Does binding energy take into account the KE? Maybe it does.
You mean like this

m(v^2/Ro) = GMm/Ro^2 ????

Well binding energy is the energy required for the orbiting satellite to escape. So the total energy should be zero....

Well yes Ek is included...

Eg + Ek = Et1
- GMm/Ro + 1/2GMm/Ro = - 1/2 GMm/Ro

Et1 + Eb = Et2
- 1/2 GMm/Ro + Eb = 0 J
Eb = 1/2 GMm/Ro
 
  • #4
haruspex
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You mean like this

m(v^2/Ro) = GMm/Ro^2 ????
Yes.
Well binding energy is the energy required for the orbiting satellite to escape. So the total energy should be zero....

Well yes Ek is included...
OK.
 

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