Satellite Orbiting around the Earth (gravitational fields)

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SUMMARY

The discussion focuses on calculating the radius of a satellite's orbit around the Earth, given a gravitational force of 3000N acting on a 500 kg satellite. Using the gravitational force equation, FG = GM1M2/r², the radius is determined to be approximately 8.15 x 106 meters. The participant clarifies that the problem requests the radius of the orbit, not the altitude, confirming that no subtraction of Earth's radius is necessary for this calculation.

PREREQUISITES
  • Understanding of gravitational force equations, specifically FG = GM1M2/r²
  • Familiarity with the concept of circular orbits
  • Knowledge of the gravitational constant (G = 6.67 x 10-11 N(m/kg)²)
  • Basic understanding of mass and radius of Earth (Mass = 5.98 x 1024 kg, Radius = 6.38 x 106 m)
NEXT STEPS
  • Research the implications of gravitational force on satellite motion
  • Learn about orbital mechanics and the relationship between radius and velocity
  • Explore the effects of varying satellite mass on gravitational force
  • Investigate how altitude affects satellite communication and data transmission
USEFUL FOR

Students studying physics, aerospace engineers, and anyone interested in satellite dynamics and gravitational effects in orbital mechanics.

HarleyM
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Homework Statement


A 500 kg satellite experiences a gravitational force of 3000N while moving in a circular orbit around the Earth.

Find the radius of the orbit

Homework Equations



FG=GM1M2/r2
g=GME/r2

Mass of Earth= 5.98x1024 Kg
Radius of Earth= 6.38x106 m

The Attempt at a Solution




Fnet=FG
3000N=GMEMS/r2
r=√[(6.67x10-11)(5.98x1024)(500)/3000]
r= 8.15x106

DO I subtract the radius of the Earth from my answer for radius of sattellite? OR would that give me the altitude, and they just want radius?
 
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Well, they did ask for radius, not altitude.
 
Ya I kind of answered my own question as I typed it up here, thanks for the advice
 

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