Energy stored in a Capacitor derivation

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SUMMARY

The energy stored in a capacitor is derived from the relationship between electric potential difference and charge movement, defined by the equation U = 1/2 QV. This derivation clarifies that the work done by the battery in transferring charges is not uniform; as charges accumulate on the plates, the resistive force increases, necessitating more work for subsequent charges. Thus, the total work done translates to the stored energy in the capacitor, which is influenced by the capacitance voltage V.

PREREQUISITES
  • Understanding of electric potential difference and charge movement
  • Familiarity with the concept of work in physics
  • Knowledge of capacitor fundamentals and energy storage
  • Basic grasp of electric fields and capacitance
NEXT STEPS
  • Study the derivation of the energy stored in capacitors using calculus
  • Explore the relationship between capacitance and voltage in different capacitor types
  • Learn about the impact of resistive forces on charge movement in capacitors
  • Investigate practical applications of capacitors in electronic circuits
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Physics students, electrical engineers, and anyone interested in understanding energy storage mechanisms in capacitors.

gkangelexa
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Electric potential difference is defined as the potential energy difference (work difference) per unit charge, when this charge q is moved between points b and a.
so Ub - Ua = qVba

Said in other words, if an object with charge q is moved through a potential difference Vba then its potential energy changes by an amount qVba


How do you relate those equations to this one concerning Electric energy storage in a capacitor? U = 1/2 QV

Why is W = U = 1/2QV for a capacitor
instead of W = U = qV as above?
 
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That's a very good question.

It is addressed here:

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capeng2.html

The work done by the battery, let's say, in moving ALL of the charges from plate to the other is not the same for all the charges. The first one doesn't encounter much resistive force, but as more and more charges accumulate on one plate, more work has to be done to do the charge transfer. The total amount of work done at the end is the store energy and the capacitance voltage V.

So when you move a charge at the end against the potential V, you are doing work against the "full field", which is different than the stored field.

Zz.
 
thanks youre brilliant!
 

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