Energy-Time Uncertainty Relation

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SUMMARY

The discussion centers on the derivation of the energy-time uncertainty relation from the position-momentum uncertainty principle. The user attempts to manipulate equations involving position (dx), momentum (p), energy (e), frequency (ν), wavelength (λ), and the speed of light (c) to establish a relationship between energy and time uncertainty (σe.σt≥4π). However, it is clarified that while the symbolic manipulation is insightful, the energy-time uncertainty relation lacks the rigorous definition present in the position-momentum case, as highlighted in Shankar's "Principles of Quantum Mechanics".

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically the uncertainty principle.
  • Familiarity with mathematical manipulation of physical equations.
  • Knowledge of Fourier transforms and their application in quantum mechanics.
  • Basic concepts of wave-particle duality and non-commutative operators.
NEXT STEPS
  • Study Shankar's "Principles of Quantum Mechanics" for a deeper understanding of energy-time uncertainty.
  • Explore the mathematical foundations of non-commutative operators in quantum mechanics.
  • Learn about Fourier transforms and their implications in quantum state analysis.
  • Investigate the implications of the uncertainty principle in various quantum systems.
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Students and professionals in physics, particularly those focusing on quantum mechanics, as well as researchers exploring the implications of the uncertainty principle in theoretical and experimental contexts.

harjyot
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I was trying to Go from the uncertainty principle to its energy-time counter part. i know the maths is a bit off,but the idea is correct?

dx=position
p=momentum
e=energy
[itex]\upsilon[/itex]=frequency
[itex]\lambda[/itex]=wavelength
c=velocity of electromagnetic radiations
dt=time

now ,
[itex]\lambda[/itex]=h/p....(i)
c=[itex]\upsilon[/itex].[itex]\lambda[/itex]....(ii)

e=h.[itex]\upsilon[/itex]
e=(h.c)/[itex]\lambda[/itex]

replacing [itex]\lambda[/itex]'s value here from (i)

e=(h.c)/(h/p)
e=c.p

now c = velocity of light , it can be written as dx/dt
e= (dx/dt).p
multiplying by dt on both sides

e.dt=(dx/dt).dt.p
e.dt=dx.p

Therefore frome this relation if we straight away incorporate this in place of the
σx.σp≥h/4π

cannot we get
σe.σt≥4π
 
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harjyot said:
I was trying to Go from the uncertainty principle to its energy-time counter part. i know the maths is a bit off,but the idea is correct?

dx=position
p=momentum
e=energy
[itex]\upsilon[/itex]=frequency
[itex]\lambda[/itex]=wavelength
c=velocity of electromagnetic radiations
dt=time

now ,
[itex]\lambda[/itex]=h/p....(i)
c=[itex]\upsilon[/itex].[itex]\lambda[/itex]....(ii)

e=h.[itex]\upsilon[/itex]
e=(h.c)/[itex]\lambda[/itex]

replacing [itex]\lambda[/itex]'s value here from (i)

e=(h.c)/(h/p)
e=c.p

now c = velocity of light , it can be written as dx/dt
e= (dx/dt).p
multiplying by dt on both sides

e.dt=(dx/dt).dt.p
e.dt=dx.p

Therefore frome this relation if we straight away incorporate this in place of the
σx.σp≥h/4π

cannot we get
σe.σt≥4π

Your derivation only works symbolically (and is a good way to convince youself of the idea), as some of the equations above are meaningful only in a narrow range of applications. The uncertainty principle for position-momentum has a rigorous definition and proof (which is caused by the non-commutative relation of X and P operator), but not the energy-time relation. A better explanation for the energy-time uncertainty I've seen is from Shankar's Principles of Quantum Mechanics, this is due to the fact that particles' life time is only finite (at least on the one end), thus its Fourier transform into the frequency domain fails to peak at a single frequency, instead will be spreaded - causing the uncertainty in energy measurement.
 

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