Energy Transfer by Work from Steam to Piston - 5kg Steam Expansion

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SUMMARY

The discussion centers on the energy transfer by work from steam to a piston during the expansion of 5 kg of steam in a piston-cylinder assembly. The specific internal energies are u1 = 2709.9 kJ/kg and u2 = 2659.6 kJ/kg, with heat transfer of 80 kJ and work input from a paddle wheel of 18.5 kJ. The energy transfer by work from the steam to the piston can be calculated using the first law of thermodynamics, specifically the equation Q = u2 - u1, which accounts for the heat and work interactions.

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A 5 kg of steam contained within a piston-cylinder assembly undergoes an
expansion from state1, where the specific internal energy is u1 2709.9 kJ/kg,to state 2, where u2 2659.6 kJ/kg. During the process, thereis heat transfer to the steam with a magnitude of 80 kJ. Also, a paddle wheel transfers energy to the steam by work in theamount of 18.5 kJ. There is no significant change in the kinetic or potential energy of the steam. Determine the energytransfer by work from the
steam to the piston duringthe process, in kJ.

Anybody have an idea as to how this can be answered?
 
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Equation

u = uf + x(ug-uf) Q= u2-u1

Should i use this equation or which one?
 

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