Thermodynamics problem - internal energy of a saturated steam?

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SUMMARY

The internal energy at state 1 for saturated steam is defined solely by the vapor phase, represented as U_vap. The discussion clarifies that even though saturated steam consists of both liquid and gas phases, the internal energy calculation for saturated steam at a specific state does not include the liquid phase energy (U_liq). The values obtained from the steam tables for state 1 are P1 = 500 kPa, T1 = 425.65 K, and specific volume v1 = 0.37297. The work done by the steam from state 1 to state 3 is calculated as W(state 1->3) = 232.3 kJ/kg.

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theBEAST
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Homework Statement


6JBYYAS.png


For those who are not interested in reading through the different values I get for each stage then please answer this question:

What is the internal energy at state 1? When water is a saturated steam... Is it U_vap + U_liq since saturated steam has both liquid and gas phases in it? Or is it just U_vap?

If you are confused it may be worthwhile to see what each state is in the following text I wrote:

Thanks!


In this question there are 3 states. The question also has three parts to it.

First Part:
Find the initial pressure, temperature and specific volume values at state 1 from the steam tables and appendices. I ended up getting these values (these are correct as I have checked the answer key):
P1 = 500kPa
T1 = 425.65K
v(specific volume)1 = 0.37297

Second Part:
Find the work done by the steam. I calculated this and got the same answer as the answer key which is:
W(state 1->3) = 232.3 kJ/kg Note they want the answer in specific energy

Third Part:
This is where I am stuck. This one asks for the total heat transferred to the steam.

I know that:
H = ΔU + W

Where ΔU is the change in internal energy from state 1 to state 3. My main problem concerns solving for the internal energy in state 1 using the steam tables. First off state 1 is saturated steam, so from the Thermodynamics tables I get several internal energy values. I get U_vap, U_liq and U_evap. From what I have learned a saturated steam includes water in both liquid and gas phases? Thus U(state 1) = U_vap + U_liq...?

This does not work and the answer suggests that U(state 1) = U_vap only.
 
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theBEAST said:

Homework Statement


6JBYYAS.png


For those who are not interested in reading through the different values I get for each stage then please answer this question:

What is the internal energy at state 1? When water is a saturated steam... Is it U_vap + U_liq since saturated steam has both liquid and gas phases in it? Or is it just U_vap?

If you are confused it may be worthwhile to see what each state is in the following text I wrote:

Thanks!


In this question there are 3 states. The question also has three parts to it.

First Part:
Find the initial pressure, temperature and specific volume values at state 1 from the steam tables and appendices. I ended up getting these values (these are correct as I have checked the answer key):
P1 = 500kPa
T1 = 425.65K
v(specific volume)1 = 0.37297

Second Part:
Find the work done by the steam. I calculated this and got the same answer as the answer key which is:
W(state 1->3) = 232.3 kJ/kg Note they want the answer in specific energy

Third Part:
This is where I am stuck. This one asks for the total heat transferred to the steam.

I know that:
H = ΔU + W

Where ΔU is the change in internal energy from state 1 to state 3. My main problem concerns solving for the internal energy in state 1 using the steam tables. First off state 1 is saturated steam, so from the Thermodynamics tables I get several internal energy values. I get U_vap, U_liq and U_evap. From what I have learned a saturated steam includes water in both liquid and gas phases? Thus U(state 1) = U_vap + U_liq...?

This does not work and the answer suggests that U(state 1) = U_vap only.

I can not see the image. Can you re-upload it please ? Also absolute internal energy of the system is undefined. (Think why ?)
 
Dear beast,

The term "saturated steam" refers only to the vapor.

Chet
 

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