Energy Transfer in Collision of 200000N & 400000N Cars

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SUMMARY

The discussion centers on calculating the energy transfer during a collision between a 200,000 N car traveling at 3 m/s and a stationary 400,000 N car. The key principle applied is the conservation of momentum, which allows for the determination of kinetic energy (KE) before and after the collision. The difference in KE indicates the energy lost to other forms during the collision. The final calculations reveal the specific amount of energy transferred, emphasizing the importance of understanding momentum in collision scenarios.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of kinetic energy calculations
  • Familiarity with conservation of momentum principles
  • Basic grasp of energy transformation concepts
NEXT STEPS
  • Study the principles of conservation of momentum in elastic and inelastic collisions
  • Learn how to calculate kinetic energy using the formula KE = 0.5 * m * v²
  • Explore energy transformation during collisions in physics
  • Investigate real-world applications of collision analysis in automotive safety
USEFUL FOR

Physics students, automotive engineers, and anyone interested in understanding energy transfer during collisions.

Tubs
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This question is making me go in circles, any tips?

A car weighing 200000 N traveling 3 m/s slams into a stationary car weighing 400000 N. The collision connects the two cars. How much energy is transferred from kinetic energy to other forms of energy in the collision?
 
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In this question, the energy of the system (ie ,the two cars) is not conserved. You have to find the KE of the cars before and after collision and the difference would give you the KE lost to other forms.
Can you find this difference? (Hint: Conservation of momentum)
 

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