ThomasT said:
I disagree. The qm formulation does assume that they're analyzing the same thing. What it doesn't do is specify any particular value wrt any particular coincidence interval for that common property. So, we apparently do have common cause and analysis of a common property producing experimental violation of the inequalities.
That's simply because in the blunt application of quantum theory in the standard interpretation, we do 'action at a distance' when the first measurement "collapses" the ENTIRE wavefunction, so also the part that relates to the second particle. So this collapse includes the angular information of the first measurement, in exactly the same way as the single light disturbance that goes through two consecutive polarizers. This is why formally, in quantum mechanics, both are very similar.
If this collapse corresponds to anything physical, then that stuff does "action at a distance", and hence Bell's inequalities don't count anymore of course, as he assumes that we do not have a signal from one side about the chosen measurement, when we measure the second side.
But in as much with the 2 consecutive polarizers, one could easily imagine that the "light disturbance" carries with it, as a physical carrier, the "collapse information" from the first to the second (and has to do so at less than lightspeed because the disturbance doesn't go faster), there's no physical carrier, and it goes faster than light, with an Aspect-like setup.
Suppose you have an optical Bell setup where you've located the A side a bit closer to the emitter than the B side so that A will always record a detection before B. It's a detection at A that starts the coincidence circuitry which then selects the detection attribute (1 for detection and 0 for no detection) associated with a certain time interval at B to be paired with the detection attribute, 1, recorded at A.
Yes, but the CHOICE of which measurement to perform at B has been done before any signal (at lightspeed) could reach B. THAT's the point. Not to sort out which pairs of detection go together. BTW, you don't even need that. You could put the two sides A and B a lightyear apart, and just have them well-synchronized clocks (this can relativistically be done if you're careful). They then just record the times of arrival of the different light pulses. The experiment lasts maybe for a month. It is then only at least one year later, when both observers come together and compare their lists, that they find the correlations in their recorded measurements. So no synchronisation circuitry is needed. It's just the practical way of doing it in a lab.
The intensity of the light transmitted by the second polarizer in the polariscopic setup is analogous to the rate of coincidental detection in the optical Bell setup.
Yes.
Because we're always recording a 1 at A, then this can be thought of as an optical disturbance of maximum intensity extending from the polarizer at A and incident on the polarizer at B for any coincidence interval. As in the polariscopic setup, when the polarizer at B (the second polarizer) is set parallel to A, then the maximum rate of coincidental detection will be recorded -- and the rate of coincidental detection is a function of the angular difference between the setting of the polarizer at A and the one at B, just as with a polariscope.
yes. But the problem is that this time, the B disturbance doesn't know what was measured at the A side (unless this is quickly transmitted by an action-at-a-distance phenomenon). So, when B measures at 0 degrees, should it click or not ? If A measured at 0 degrees too, and it clicked there, then it should click. So maybe this was a "0-degree disturbance". Right. But imagine now that A measured at 45 degrees and that it clicked. Should B click now ? Half of the time, of course. And what if B had measured 45 degrees instead of 0 degrees ? Should it now click with certainty ? But then it couldn't click with certainty at 0 degrees, right ? So what the disturbance should do at B must depend on what measurement A had chosen to perform: 0 degrees, 45 degrees or 90 degrees. If you work the possibilities out in all detail, you find back Bell's inequalities.
The critical assumption in Bell's theorem is that the data streams accumulated at A and B are statistically independent. The experimental violations of the inequalities don't support the idea of direct causation between A and B, or that the correlations can't be caused by analysis of the same properties. Rather, they simply mean that there is a statistical dependency between A and B. This statistical dependency is a function of the experimental design(s) necessary to produce entanglement. In the simple optical Bell tests the dependency arises from the emission preparations and the subsequent need to match detection attributes via time-stamping.
The emission preparations: does that mean that we give them the same properties ? But that was not the explanation, because of Bell. I don't see why you insist so much on this time stamping. Of course we want to analyze pairs of photons! But that doesn't explain WHY we get these Bell-violating correlations. If they were just "pairs of identical photons each time" and we were analyzing properties of these photons on both sides, then they should obey Bell's inequalities !
Look, this is as if you were going to emit two identical letters each time to two friends of you, one living in Canada, the other in China. You know somehow that they don't talk. The letters can be on blue or pink paper, they can be written with blue or red ink, and they can be written in Dutch or in Arabic. For each letter, your friends are supposed to look at only one property: they pick (free will, randomly, whatever) whether they look at the color of the paper, the color of the ink, or the language of the letter.
You ask them to write down in their logbook, what property they had chosen to look at, and what was their result. Of course you ask them also which letter they were dealing with (some can get lost in the post and so on). So you ask them to write down the postal stamp date (you only send out one pair per day).
You send pairs of identical letters out each second day.
After 2 years, you ask them to send you their notebooks. When you receive them, you compare their results. You classify them in 9 categories:
(Joe: color of paper ; Chang: color of paper)
(Joe: color of paper ; Chang: color of ink)
(Joe: color of paper ; Chang: language)
(Joe: color of ink ; Chang: color of paper)
etc...
But in order for you to be able to do that, you want them to have analysed the same pair of letters of course. So you verify the postal stamp date. Those that don't find a match, you discard them, because probably the other letter was lost in the post office somewhere.
Then for each pair, you count how much time they found the "same" answer (say, pink, red, Dutch is 1, blue, blue and Arabic is 0) and how much time they found a different answer. These are the correlations.
Of course, each time they looked at the same property, they found the same answer (they were identical letters). So when Joe looked at the color of the paper, and Chang did so too, they find 100% correlation (when Joe found blue, Chang found blue, and when Joe found pink, Chang found pink).
You also find that the correlations are symmetrical: when Joe looked at "paper" and Chang at "ink" then that gives the same result of course as when Joe looked at "ink" and Chang at "paper". So there are actually 3 numbers which are interesting:
C(Joe: paper, Chang: ink) = C(Joe: ink, Chang: paper) = C(1,2)
C(Joe: paper, Chang: language) = C(Joe: language, Chang: paper) = C(1,3)
C(Joe: language, Chang: ink) = C(Joe: ink, Chang: language) = C(2,3)
Well, Bell shows that these correlations obey his inequalities.
That is: C(1,2) + C(2,3) + C(1,3) > 1
You cannot have that each time that Joe looked at "paper" and Chang at "ink" they found opposite results (C(1,2) close to 0)), that each time Joe looked at paper, and Chang looked at "language" that they found opposite results (C(1,3) close to 0) and at that each time Joe looked at "language" and Chang looked at "ink" that they ALSO found opposite results (C(2,3) close to 0). If you think about it, it's logical!
You would have a hell of a surprise to find that Joe and Chang had Bell-violating correlations.
There doesn't exist a set of letters you could have sent that can produce Bell-violating inequalities if the choices of measurement are random and independent.
The only solution would have been that Joe and Chang cheated, and called each other on the phone to determine what measurements they'd agree upon.