Enthelpy of a Neutralization Reaction

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Discussion Overview

The discussion centers around the enthalpy change of a neutralization reaction between NaOH and HCl, particularly when NaOH is in solid form rather than aqueous. Participants explore the implications of state changes on enthalpy and the nature of the reaction products.

Discussion Character

  • Homework-related
  • Exploratory
  • Technical explanation

Main Points Raised

  • One participant suggests that there may be no enthalpy change when NaOH is solid due to state changes, referencing Hess' law.
  • Another participant proposes that the enthalpy change could be greater (more negative) when NaOH is solid, implying a lower final enthalpy, but seeks clarification on the reasoning behind this.
  • Several participants confirm the reaction products of the neutralization are NaCl and H2O.
  • A question is raised about the use of fractions in thermochemical equations, with a participant explaining that enthalpy is often reported per mole of reaction or reactant, allowing for normalization.
  • One participant notes that the dissolution of salt is typically exothermic, particularly for anhydrous salts.

Areas of Agreement / Disagreement

Participants generally agree on the reaction products and the nature of dissolution but express uncertainty regarding the enthalpy change when NaOH is in solid form. The discussion remains unresolved regarding the specific enthalpy implications of the state change.

Contextual Notes

Participants have not fully resolved the assumptions regarding the enthalpy change related to the physical states of the reactants and the implications of dissolution on the overall enthalpy of the reaction.

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Homework Statement


Say there was an experiment between NaOH and HCl. The reaction is a neutralization reaction resulting in NaCl and H2O. The question is: What if the two reactants weren't aqueous, but if NaOH was in solid pellets instead?

Homework Equations


Neutralization reactions are usually exothermic.

The Attempt at a Solution


I initially thought there would be no enthalpy change because it's just changing the states...and according to Hess' law..it doesn't matter.

But the answer, I think, is that the enthalpy change is supposed to be greater (more negative)...meaning a lower final enthalpy.

But I need help explaining why? Something to do with dissolving, breaking bonds between Na+ and Cl-...and water...
 
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You are on the right track. What are reaction products?
 
Borek said:
You are on the right track. What are reaction products?

The reaction is a neutralization reaction resulting in NaCl and H2O...right?
 
Another question on the tangent of thermochemistry -

Why are fractions allowed in thermochemical equations but not otherwise?
 
elasticities said:
The reaction is a neutralization reaction resulting in NaCl and H2O...right?

Yes. What happens when you have water and salt?

As to the fractions - enthalpy is often reported per mole of reaction or mole of reactant - these don't have to be identical. Sometimes using fractions for other substances you can "normalize" reaction so that it contains one mole of the substance you are interested in.

Note that technically whether coefficients are smallest integers or not doesn't matter, it is stoichiometric ratio of reagents that is important. Using smallest integer is just a convention that makes comparison easier and put some order.
 
Borek said:
Yes. What happens when you have water and salt?

The salt dissolves...? I'm sorry...I still don't get it. :S

Thanks for explaining my other question, by the way. :) Much appreciated.
 
Salt dissolves, that's right. Dissolution is (especially in the case of anhydrous salts) almost always exothermic.
 

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