Entropy in system of non-degenerate atoms

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SUMMARY

The discussion focuses on calculating the entropy of a system of non-degenerate multi-level atoms all in their lowest energy state. It is established that the degeneracy function, Ω, equals 1 in this scenario, leading to the conclusion that the entropy, S, can be calculated using the equation S = kbTln(Ω). Additionally, the relationship between temperature and entropy is highlighted, indicating that temperature can be derived from the equation 1/T = ΔS/ΔE.

PREREQUISITES
  • Understanding of statistical mechanics concepts
  • Familiarity with the Boltzmann constant (kb)
  • Knowledge of thermodynamic equations, specifically S = kbTln(Ω)
  • Basic principles of energy states in atomic systems
NEXT STEPS
  • Explore the implications of degeneracy in thermodynamic systems
  • Study the relationship between entropy and temperature in detail
  • Learn about the calculation of entropy in various atomic configurations
  • Investigate advanced statistical mechanics topics, such as the canonical ensemble
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Students and professionals in physics, particularly those studying thermodynamics and statistical mechanics, as well as researchers focusing on atomic and molecular systems.

vodkasoup
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Hi all,

1. Homework Statement

A system of non-degenerate multi-level atoms are all in their lowest energy state. Calculate the entropy of the system.

Homework Equations



S = kbTln(Ω)

S = Q / T

dU = TdS - pdV

The Attempt at a Solution



I'm not sure how to proceed. I know that Ω is the degeneracy function. If all of the atoms in the system are non-degenerate and in their lowest energy level, does this value equal 1 ? If the atoms are in their lowest energy state, what does this say about the temperature?

Many thanks for your help.
 
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vodkasoup said:
I'm not sure how to proceed. I know that Ω is the degeneracy function. If all of the atoms in the system are non-degenerate and in their lowest energy level, does this value equal 1 ? If the atoms are in their lowest energy state, what does this say about the temperature?

Many thanks for your help.
Indeed Ω = 1. This is enough to calculate the entropy. Temperature is often identified by ##1/T = \Delta S/ \Delta E##, so I suppose we could attempt to calculate it this way but it might be more work.
 
Last edited:

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