Epsilon delta to prove continuity

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james.farrow
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I have an example bit I can't quite follow it...?

Use epsilon -delta definition of continuity to prove f(x) = 3x^2 - x is continuous at x=2

Ep > 0 and delta > 0 in terms of Ep

f(x) -f(2) = 3x^2 - x -(3*2^2 -2)

f(x) - f(2) = 3x^2 -x - 10
f(x) - f(2) = (3x + 5)(x - 2)

So far so good - but now can someone explain what happens please...!

James
 
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Well, we may, for example, rewrite 3x+5 as 3(x-2)+11.

Now, set d=x-2

We then have:
|f(x)-f(2)|=|(3d+11)d|<=3|d|^2+11|d|<=14|d|, if |d| is tiny enough, specifically, when |d|<1 (i.e, when x is between 1 and 3)

Now, can you make |d| so small that given any e, 14|d| will be smaller than e?
 
Hi James! :smile:

(have a delta: δ and an epsilon: ε and try using the X2 tag just above the Reply box :wink:)
james.farrow said:
Use epsilon -delta definition of continuity to prove f(x) = 3x^2 - x is continuous at x=2

Ep > 0 and delta > 0 in terms of Ep

f(x) -f(2) = 3x^2 - x -(3*2^2 -2)

You're probably wondering "wherever does δ come into it?? :confused:"

You needed to start with "f(2 + δ) -f(2) = …" :wink:
 
Thanks for the replies lads - I appreciate it! What I need is an explanantion of the whole epsilon delta thing really from start to finish.

I don't understand it to be honest and I need to so I can apply it to other functions etc

Many thanks

James
 
james.farrow said:
Thanks for the replies lads - I appreciate it! What I need is an explanantion of the whole epsilon delta thing really from start to finish.

I don't understand it to be honest and I need to so I can apply it to other functions etc

Many thanks

James

Start with the first thing you don't understand.