MHB Equation for the horizontal asymptote.

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To find the horizontal asymptote of the function g(x) = -2f(2x - 6), where f(x) = 4^x, one must first identify the horizontal asymptote of f(x). The function f(x) approaches 0 as x approaches negative infinity, indicating that its horizontal asymptote is y = 0. Since g(x) is a transformation of f(x), the horizontal asymptote remains unchanged by vertical shifts or reflections. Therefore, the horizontal asymptote for g(x) is also y = 0. Understanding the behavior of exponential functions is key to determining their asymptotic properties.
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How would you find the equation for the horizontal asymptote of the following exponential function?:
$$g(x) = -2f(2x - 6)$$

Let $$f(x) = 4^x$$
 
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I would begin by looking at the horizontal asymptote of $f$...can you see what this is?
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

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