Equation of a plane perpendicular to another plane

Click For Summary
SUMMARY

The discussion focuses on finding the equation of a plane that is perpendicular to the plane defined by the equation 5x + 4y - 3z = 8 and passes through the line defined by x = 2y = 3z. To solve this problem, one must identify the normal vector of the given plane, which can be derived directly from its coefficients. The user is advised to consult resources on analytic geometry for a deeper understanding of lines and planes in space.

PREREQUISITES
  • Understanding of normal vectors in geometry
  • Familiarity with the standard form of a plane equation (Ax + By + Cz = D)
  • Basic knowledge of lines in three-dimensional space
  • Experience with analytic geometry concepts
NEXT STEPS
  • Study the properties of normal vectors in relation to planes
  • Learn how to derive equations of lines from parametric equations
  • Explore the concept of perpendicularity in three-dimensional geometry
  • Read about the equations of planes in analytic geometry
USEFUL FOR

Students studying analytic geometry, educators teaching geometry concepts, and anyone seeking to understand the relationship between lines and planes in three-dimensional space.

Josie Jones
Messages
3
Reaction score
0
Hi, I am really stuck! I need to find the equation of the plane through the line x=2y=3z perpendicular to the plan 5x+4y-3z=8. Can anyone give me any pointers of where to start with this? Not expecting a full solution, just an idea of where to start.

THanks!
 
Physics news on Phys.org
I moved this thread to our homework section. Can you find a line (or just a vector) that is perpendicular to the second plane? What do you know about that line (or vector) relative to one of the planes you are looking for?
 
mfb, thanks for moving the thread.

I don't know how to find a perpendicular line or vector. I think it is a normal vector, but I have not been shown how to do this. I found this question in a book and am unsure how to proceed.

thanks for your reply
 
Josie Jones said:
Hi, I am really stuck! I need to find the equation of the plane through the line x=2y=3z perpendicular to the plan 5x+4y-3z=8.

Josie Jones said:
I don't know how to find a perpendicular line or vector. I think it is a normal vector, but I have not been shown how to do this. I found this question in a book and am unsure how to proceed.
If the book was a textbook on analytic geometry it should have sections on the equations of lines and planes in space, and how to determine the orientation of these objects.

Given the equation of a plane in standard form, Ax + By + Cz = D, it is very simple to find a normal to the plane. It's also straightforward to find a vector in the direction of a line.

Since you haven't made much of an effort, which is required for homework posts, I am closing this thread. Please go back and do some digging in your book. Another resource is this wikipedia article on planes -- https://en.wikipedia.org/wiki/Plane_(geometry). I'm sure they also have an article on lines in space.
 
  • Like
Likes   Reactions: Greg Bernhardt

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
17
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
Replies
1
Views
2K
Replies
1
Views
2K
Replies
8
Views
3K