Equation of Curve Passing Through (0, 9)

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SUMMARY

The discussion focuses on finding the equation of a curve that passes through the point (0, 9) and has a slope at any point P that is twice the y-coordinate of P. The differential equation derived from this property is y'(x) = 2*y(x). Solving this first-order linear differential equation leads to the general solution y(x) = Ce^(2x), where C is a constant determined by the initial condition y(0) = 9, resulting in the specific solution y(x) = 9e^(2x).

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Homework Statement



A curve passes through the point (0, 9) and has the property that the slope of the curve at every point P is twice the y-coordinate of P. What is the equation of the curve?

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The Attempt at a Solution



im thinking the slope would then be 18...but i haven't gotten much farther than that
 
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Keep in mind that derivative equals slope at a given point.
 
EstimatedEyes said:
Keep in mind that derivative equals slope at a given point.

Right. And slope=derivative. So you want to solve the differential equation y'(x)=2*y(x).
 

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