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Equation of the type mdx+ndy=0

  1. Mar 1, 2007 #1
    1. The problem statement, all variables and given/known data



    2. Relevant equations

    3. The attempt at a solution

    At first I thought it was a simple equation of the type mdx+ndy=0, but when I integrated m wrt x and ignored all terms containing x in n (all of them in this case), and added, I didnt get the solution.
    Last edited by a moderator: Jul 15, 2014
  2. jcsd
  3. Mar 1, 2007 #2


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    The problem looks suspiciously like it was intended to be an exact equation but something messed up in transcribing it. Because it's not.
  4. Mar 1, 2007 #3
    Yes...it does look like it would be an exact equation, but it's not quite there.

    Is there anything we can do to make it so?

    how about finding an integrating factor to multiply through in order to convert it to exact?



    is a function of x only, then the solution to:

    [tex]\frac{d\mu}{dx} = \frac{My-Nx}{N} \mu [/tex]

    gives [tex]\mu[/tex] as the appropriate integrating factor

    or if


    is a function of y only, then the solution to:

    [tex]\frac{d\mu}{dx} = \frac{Nx-My}{M} \mu[/tex]

    gives you the integrating factor, [tex]\mu[/tex]
    Last edited: Mar 1, 2007
  5. Mar 1, 2007 #4


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    Sure enough. There IS an integrating factor. Can you find it, chaoseverlasting?
  6. Mar 4, 2007 #5
    No man. I have no idea what you guys are doing. The only integrating factor I know of is in the Linear DE. I dont think I can reduce this to a LDE
  7. Mar 5, 2007 #6


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    Then I strongly suggest you go back to your textbook and review "exact equations" and "integrating factors"!
  8. Mar 12, 2007 #7
    The thing is, Im not even in college yet. I have a basic understanding of what DE's are but this one came in an exam. We havent done this sort of thing.
  9. Mar 12, 2007 #8


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    We believe you. :rolleyes:
  10. Mar 12, 2007 #9


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    Well, then just try and multiply the equation by x^n. Then apply the exactness test (dM/dy=dN/dx) and determine an n that works. Then go back and try your integration again. That's an example of an integrating factor.
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